Given:
Inductance, L = 150 mH
Capacitance, C = 5.00 mF
= 240 V
frequency, f = 50Hz
= 100 mA
Solution:
To calculate the parameters of the given circuit series RLC circuit:
angular frequency,
= ![2\pi f = 2\pi \times50 = 100\pi](https://tex.z-dn.net/?f=2%5Cpi%20f%20%3D%202%5Cpi%20%5Ctimes50%20%3D%20100%5Cpi%20)
a). Inductive reactance,
is given by:
![\X_{L} = \omega L = 100\pi \times 150\times 10^{-3} = 47.12\Omega](https://tex.z-dn.net/?f=%5CX_%7BL%7D%20%3D%20%5Comega%20L%20%3D%20100%5Cpi%20%5Ctimes%20150%5Ctimes%2010%5E%7B-3%7D%20%3D%2047.12%5COmega%20)
b). The capacitive reactance,
is given by:
![X_{C} = 0.636\Omega](https://tex.z-dn.net/?f=X_%7BC%7D%20%3D%200.636%5COmega)
c). Impedance, Z = ![\frac{\Delta V_{max}}{I_{max}} = \frac{240}{100\times 10^{-3}} = 2400\Omega](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20V_%7Bmax%7D%7D%7BI_%7Bmax%7D%7D%20%3D%20%5Cfrac%7B240%7D%7B100%5Ctimes%2010%5E%7B-3%7D%7D%20%3D%202400%5COmega%20)
![Z = 2400\Omega](https://tex.z-dn.net/?f=Z%20%3D%202400%5COmega)
d). Resistance, R is given by:
![2400^{2} = R^{2} + (47.12 - 0.636)^{2}](https://tex.z-dn.net/?f=2400%5E%7B2%7D%20%3D%20R%5E%7B2%7D%20%2B%20%2847.12%20-%200.636%29%5E%7B2%7D)
![R = \sqrt {5757839.238}](https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%20%7B5757839.238%7D)
![R = 2399.5\Omega](https://tex.z-dn.net/?f=R%20%3D%202399.5%5COmega)
e). Phase angle between current and the generator voltage is given by:
![tan\phi = \frac{X_{L} - X_{C}}{R}](https://tex.z-dn.net/?f=tan%5Cphi%20%3D%20%5Cfrac%7BX_%7BL%7D%20-%20X_%7BC%7D%7D%7BR%7D)
![\phi =tan^{-1}( \frac{X_{L} - X_{C}}{R})](https://tex.z-dn.net/?f=%5Cphi%20%3Dtan%5E%7B-1%7D%28%20%5Cfrac%7BX_%7BL%7D%20-%20X_%7BC%7D%7D%7BR%7D%29)
![\phi =tan^{-1}( \frac{47.12 - 0.636}{2399.5}) = tan^{-1}{0.0.01937}](https://tex.z-dn.net/?f=%5Cphi%20%3Dtan%5E%7B-1%7D%28%20%5Cfrac%7B47.12%20-%200.636%7D%7B2399.5%7D%29%20%3D%20tan%5E%7B-1%7D%7B0.0.01937%7D)
![\phi = 1.11^{\circ}](https://tex.z-dn.net/?f=%5Cphi%20%3D%201.11%5E%7B%5Ccirc%7D)
Horizontal distance covered by a projectile is X = Vix *T
where Vix is the initial horizontal component of velocity and T is time taken by the projectile
Vix = ViCos theta
In question they said that initial velocity and angle is same on earth and moon
so Vix would remains same
now let's see about time taken T
time taken to reach the highest point
Vfy = Viy +gt
at highest point vertical velocity become zero so Vfy =0
0 = Vi Sin theta + gt
t = Vi Sintheta /g
Total time taken to land will be twice of that
On earth
Te= 2t
Te = 2Sinθ/g
on moon g is one-sixth of g(earth)
Tm = 2Sinθ/(g/6)
Tm = 6(2Sinθ/g)
Tm = 6Te
so total time taken by the projectile on moon will be six times the time taken on earth
From first equation X = Vix*T
we can see that X will also be 6 times on moon than earth
so projectile will cover 6 times distance on moon than on earth
The correct answer is:
<span>C: in the protons and neutrons of an atom
In fact, the nuclear energy refers to the binding energy of the nucleons (protons and neutrons) of an atom. The protons and the neutrons are held together by the strong nuclear interaction, one of the four fundamental forces of nature, and the energy associated to this interaction is called nuclear energy.
</span>
Answer: static stretching
Explanation:
e.g rubberband
the answer choice will be A because they travel at the same speed through only light not one material.