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Tresset [83]
3 years ago
14

Which one of the following is NOT a simple machine?

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
It is a hammer because hammers are not examples of a simple machine
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A vertical spring stretches 3.4 cm when a 12-g object is hung from it. The object is replaced with a block of mass 26 g that osc
Mariulka [41]

Answer:

Period of motion is approximately 0.5447  seconds

Explanation:

We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)

F = k * x

0.012 kg * 9.8  m/s^2 = k 0.034 m

k = 0.012 kg * 9.8  m/s^2 / (0.034 m)

k = 3.46 N/m

now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':

T=2\pi\,\sqrt{\frac{m}{k} }

which in our case becomes:

T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec

4 0
3 years ago
Answer all of them an you will get the brain list
Vlad [161]

Answer:

4. Force = 178.6 Newton.  

5. Acceleration = 2.28 m/s².

6. Force = 178.6 Newton.

Explanation:

4. Given the following data;

Acceleration = 3.8 m/s²

Mass = 47kg

Force = mass * acceleration

Force = 47 * 3.8

<em>Force = 178.6 Newton. </em>

5. Given the following data;

Force = 785N

Mass = 345kg

Acceleration = force/mass

Acceleration = 785/345

<em>Acceleration = 2.28 m/s²</em>

6. Given the following data;

Acceleration = 6m/s²

Force = 32N

Mass =force/acceleration

Mass = 32/6

<em>Mass = 5.33 kilograms </em>

5 0
3 years ago
Stellar evolution is _____. the process of planetary formation the life cycle of a star the death of a star how comets form
frosja888 [35]
B.) Stellar evolution is "<span>the life cycle of a star"

Hope this helps!</span>
8 0
3 years ago
Read 2 more answers
La trayectoria de vuelo del helicóptero cuando despega desde A esta definida por las ecuaciones x=2t^2 m y y=0.04t^3 m, donde t
Yuri [45]

Answer:

The flight path of the helicopter when it takes off from A is defined by the equations x = 2t ^ 2 m and y = 0.04t ^ 3 m, where t is the time in seconds. Determine the distance the helicopter is from point A and the magnitudes of its speed and acceleration when t = 10 s

Explanation:

Given that,

The path curve are

x = 2t²

y = 0.04t³

Distance from A. When t = 10s

The position on the x axis at t=10s is

x = 2t²

x = 2×10² = 200m

The position on y axis at t= 10s is

y = 0.04t³

y = 0.04 ×10³ = 40m

So, the plane it at (200,40) and it started for (0,0)

From geometry we can find distance between the two point using

D = √(x2-x1)² + (y2-y1)²

D = √(200-0)²+(40-0)²

D = √200²+40²

D = 203.96m

So, the distance is approximately 204m

b. The magnitude of the speed.

Speed is give as the differentiation of distance

So, for x curve, at t =10

Vx = dx/dt = 4t

Vx = 4×10 = 40m/s

Also, for y axis at t=10

Vy = dy/dt = 0.12t²

Vy = 0.12×10² = 12m/s

Then, the velocity at 10s is

V = √(Vx²+Vy²)

V = √40²+12²

V = 41.76m/s

The velocity helicopter at t=10s is 41.76m/s

c. The acceleration at t=10s?

We need to find acceleration of the curve and it is given as

a = d²x/dt²

So, for x axis at t=10

ax= d²x/dt² = 4

ax = 4m/s²

Also, for y axis at t=10

ay= d²y/dt² = 0.24t

ay = 0.24 ×10 = 2.4m/s²

Then, the magnitude of acceleration at t=10s is

a = √(ay²+ax²)

a = √2.4²+ 4²

ay = 4.66m/s²

The acceleration of the helicopter at t=10s is 4.66m/s²

4 0
3 years ago
On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per
Rufina [12.5K]

Answer:

A.) 230 km

B.) 76.67 km/h

Explanation:

Given that On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per hour and drive for an additional two hours.

A.) How far do you go?

When driving for an hour, the distance covered will be

Distance = speed × time

Distance = 50 × 1 = 50 km

When driving for additional 2 hours, the distance covered will be

Distance = 90 × 2 = 180 km

Total distance = 180 + 50 = 230 km

b. What is your average x component of velocity?

Average Velocity = total distance/ total time

Average velocity = 230/3

Average velocity = 76.67 km/h

c. Why isn't vavg,x equal to the arithmetic average of your initial and final values of vx, (50+90)/2 = 70 km per hour

They are not equal because of the displacement is the same as distance travelled.

5 0
3 years ago
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