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Misha Larkins [42]

3 years ago

10

if you already have the time which is 4s and the initial velocity which is 9.8m/s and the acceleration which is -9.8m/s/s. what

would the dispacement be?

2 answers:

Vikentia [17]3 years ago

7 0

Answer:10

Explanation:

2+2=10

vichka [17]3 years ago

6 0

Answer:

10

Explanation:

2+8=10

6+4=10

5+5=10

7+3=10

9+1=10

3+2+4+1=10

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_heat is the amount of heat required to change the temperature of 1 gram of a substance by 1°C, and it is related to the chemica

Sedaia [141]

Answer:

specific heat

Explanation:

Specific heat is the amount of heat required to change the temperature of 1 gram of a substance by 1°C, and it is related to the chemical composition of the substance

4 0

4 years ago

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The intensity of light from a star (its brightness) is the power it outputs divided by the surface area over which it’s spread:

kow [346]

Answer:

$\frac{d_{1}}{d_{2}}=0.36$

Explanation:

1. We can find the temperature of each star using the Wien's Law. This law is given by:

$\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}$ (1)

So, the temperature of the first and the second star will be:

$T_{1}=3866.7 K$

$T_{2}=6444.4 K$

Now the relation between the absolute luminosity and apparent brightness is given:

$L=l\cdot 4\pi r^{2}$ (2)

Where:

L is the absolute luminosity
l is the apparent brightness
r is the distance from us in light years

Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂

If we use the equation (2) we have:

$\frac{L_{1}}{4\pi r_{1}^2}=\frac{L_{2}}{4\pi r_{2}^2}$

So the relative distance between both stars will be:

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{L_{1}}{L_{2}}$ (3)

The Boltzmann Law says, $L=A\sigma T^{4}$ (4)

σ is the Boltzmann constant
A is the area
T is the temperature
L is the absolute luminosity

Let's put (4) in (3) for each star.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{A_{1}\sigma T_{1}^{4}}{A_{2}\sigma T_{2}^{4}}$

As we know both stars have the same size we can canceled out the areas.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{T_{1}^{4}}{T_{2}^{4}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=0.36$

I hope it helps!

5 0

3 years ago

A charged particle decelerates as it moves from location a to location b. if va = 160 v and vb = 100 v, what is the sign of the

skelet666 [1.2K]

The sign of the charged particle is positively charged.

<h3>What is potential difference?</h3>

When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
There is potential energy stored in this charge that could flow when work is done on it.
Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
Here, voltage can be the potential differences.

The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves from higher to lower potential.

Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.

Learn more about potential difference,

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3 0

1 year ago

What is the mass of a 1.2N book?

const2013 [10]

2.8 kg .............is the mass of a 1.2 N book.

7 0

3 years ago

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Help with 2 Physics questions, WILL CHOOSE BRAINLIEST

Tju [1.3M]

1) D

2) D.) Greater than $\theta_c$

Explanation:

1)

The phenomenon of total internal reflection occurs when a ray of light hitting the interface between two mediums is totally reflected back into the original medium, therefore no refraction into the second medium occurs.

This phenomenon occurs only if two conditions are satisfied:

The index of refraction of the first medium is larger than the index of refraction of the 2nd medium
The angle of incidence is greater than a certain angle called critical angle

In picture 1, we have 4 different diagrams. In the diagrams:

The red arrow represents the incident ray
The green arrow represents the refracted ray
The blue arrow represents the reflected ray

Total internal reflection occurs when there is no refraction, therefore when there is no green arrow: this occurs only in figure D, so this is the correct option. (in figure C, there is a refracted ray but it is parallel to the interface: this condition occurs when the angle of incidence is exactly equal to the critical angle, however in this problem, the angle of incidence is greater than the critical angle, so the correct option is D)

2)

As we stated in problem 1), total internal reflection occurs when the angle of incidence is equal or greater than the critical angle. Therefore in this case, the angle of incidence must be

D.) Greater than $\theta_c$

3 0

3 years ago