The maximum speed of the object under simple harmonic motion is 0.786 m/s.
The given parameters:
- Position of the particle, y = 0.5m sin(πt/2)
<h3>Wave equation for
simple harmonic motion;</h3>
y = A sin(ωt + Ф)
where;
- A is the amplitude = 0.5 m
- ω is the angular speed = π/2
The maximum speed of the object is calculated as follows;
Thus, the maximum speed of the object under simple harmonic motion is 0.786 m/s.
Learn more about simple harmonic motion here: brainly.com/question/17315536
Answer:
Initial velocity, U = 4.5m/s
Explanation:
Given the following data;
Final velocity, v = 12m/s
Time, t = 5 seconds
Acceleration, a = 1.5m/s²
To find the initial velocity, we would use the first equation of motion.
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
12 = U + 1.5*5
12 = U + 7.5
U = 12 - 7.5
Initial velocity, U = 4.5m/s
For the first question, you got them right, for the two you left blank, initial(beginning) velocity: 2 m/s the final velocity is: 12 m/s
During freezing, energy is released by the mass of water without change in temperature. Such energy will also be required if the same mass of water has to be melted.
Then,
Number of moles = mass/molar mass = 253/18.02 =14.04 moles
Energy released = moles*molar enthalpy of fusion = 14.04*6.008 = 84.35 kJ
Answer:
E=72000J or 72kj
Explanation:
The formula is E=pt you need to convert your t from minutes to seconds before proceeding
