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3 years ago

What happens if both the maximum voltage and current are exceeded and 10W of power must be dissipated?

Physics

1 answer:

Aleksandr [31]3 years ago

3 0

Answer:

If both the maximum voltage and current are exceeded in a resistor, that the point will lie in the thermal breakdown of the resistor.

Explanation:

This indicated that there will be an abundance of free electrons which will be available freely. This abundance of the electrons in a conductor, will result in the reduction of the overall conductivity. whereas in an insulator or semiconductor this will enhance the overall conductivity.

As the point lies in the thermal breakdown, the Ohm's law is no longer valid and thus no analytical solution can be presented in this regard.

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Calculate the rate of heat conduction through a layer of still air that is 1 mm thick, with an area of 1 m, for a temperature of

max2010maxim [7]

Answer:

The rate of heat conduction through the layer of still air is 517.4 W

Explanation:

Given:

Thickness of the still air layer (L) = 1 mm

Area of the still air = 1 m

Temperature of the still air ( T) = 20°C

Thermal conductivity of still air (K) at 20°C = 25.87mW/mK

Rate of heat conduction (Q) = ?

To determine the rate of heat conduction through the still air, we apply the formula below.

$Q =\frac{KA(\delta T)}{L}$

$Q =\frac{25.87*1*20}{1}$

Q = 517.4 W

Therefore, the rate of heat conduction through the layer of still air is 517.4 W

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If you wanted to soundproof your bedroom, the best material to line the walls would be

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Answer:

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