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3 years ago

Question 6 (14 points)

Physics

1 answer:

leva [86]3 years ago

3 0

Answer:

$a=114\ m/s^2$

Explanation:

Given that,

Mass of an object, m = 3.68 kg

It is whirled in a horizontal circle of radius 881 cm or 8.81 m

The object completes 10.8 revolutions every 18.8 s.

We need to find the centripetal acceleration of the object. It is given by the formula as follows :

$a=\omega^2 r$ ...(1)

Where $\omega$ is angular velocity

10.8 revolutions = 67.85 rad

$\omega=\dfrac{67.85\ rad}{18.8\ s}\\\\=3.6\ rad/s$

Put values in equation (1)

$a=3.6^2\times 8.81\\\\a=114\ m/s^2$

So, the centripetal acceleration of the object is $114\ m/s^2$ .

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Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A

Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction.

How much work W does the motor do on the platform during this process? Enter your answer in joules to four significant figures.

The amount of work done by the motor is given by:

$W=\Delta K$

$W= 1/2*I*\omega f^2-1/2*I*\omega o^2$

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

$\omega f^2=\omega o^2+2*\alpha*\theta$

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

$\tau=I*\alpha$

$\alpha=\tau/I$ => $\alpha = 0.5rad/s^2$

Now we can calculate the final velocity:

$\omega f = 8.68rad/s$

Finally, we calculate the total work:

$W= 1/2*I*\omega f^2 = 1883.56J$

Since the question asked to "Enter your answer in joules to four significant figures.":

W = 1884J

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3 years ago

Helpp! If the box moves 12m to the right calculate the work done on the box.

Murrr4er [49]

Answer:

80 times 12=960

Explanation:

You have to do the equation for work, the equation is work= force times distance, the force here is 80newtons, the distance is 12meters, so you would do 80 times 12 to get your answer of 960

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2 years ago

A teacher did an experiment to show the movement of particles in solids, liquids, and gases. The experimental set-up is shown be

ELEN [110]

Answer: Option (B) is the correct answer.

Explanation:

In a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.

Hence, in solid substances the molecules have low kinetic energy.

Whereas in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Hence, gases are able to expand more rapidly as compared to liquids.

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4 years ago