Question

Question 6 (14 points)

Answer 1

Answer:

$a=114\ m/s^2$

Explanation:

Given that,

Mass of an object, m = 3.68 kg

It is whirled in a horizontal circle of radius 881 cm or 8.81 m

The object completes 10.8 revolutions every 18.8 s.

We need to find the centripetal acceleration of the object. It is given by the formula as follows :

$a=\omega^2 r$ ...(1)

Where $\omega$ is angular velocity

10.8 revolutions = 67.85 rad

$\omega=\dfrac{67.85\ rad}{18.8\ s}\\\\=3.6\ rad/s$

Put values in equation (1)

$a=3.6^2\times 8.81\\\\a=114\ m/s^2$

So, the centripetal acceleration of the object is $114\ m/s^2$.