Answer:
Step-by-step explanation:
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Answer:
The number of houses built in Town B is 56.
Step-by-step explanation:
We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.
Also, 70 houses were built in Town A during 210.
Let the number of houses built in Town B be 'x'.
So, according to the question;
Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B


x = 56
Hence, the number of houses built in Town B is 56.
The arc length of the semicircle is 5π units
<h3>Calculating length of an arc</h3>
From the question, we are to calculate the arc length of the semicircle
Arc length of a semicircle = 1/2 the circumference of the circle
∴ Arc length of a semicircle = 1/2 × 2πr
Arc length of a semicircle = πr
Where r is the radius
From the given information,
r = 5
∴ Arc length of the semicircle = 5 × π
Arc length of the semicircle = 5π units
Hence, the arc length of the semicircle is 5π units
Learn more on Calculating length of an arc here: brainly.com/question/16552139
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Answer:
The answer is 146
Step-by-step explanation:
The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.




Armed with the above rules, we can split up the summation into simple terms:





=> (a)
f(x)=28n-n^2=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b)
f(x) is a maximum when n=14
(c)
the maximum value of f(x) is f(14)=196