Answer:
60m
Explanation:
According to one of the equation of motions, v² = u²+2as where;
S is the distance
u is the initial velocity
v is the final velocity
a is the acceleration
Since the arrow is shot upwards, the body will experience a negative acceleration due to gravity i.e a = -g
Therefore our equation will become;
v² = u² - 2gS
Given u = 40m/s, g = 10m/s², S = 75m
Substituting to get the final velocity of the arrow we will have;
v² = 40²-2(10)(75)
v² = 1600 - 1500
v² = 100
v = √100
v = 10m/s
Total distance traveled is speed of the object × time taken
Total distance traveled = 10 × 6
= 60m
The arrow has therefore traveled 60m after 6seconds
Answer:
The K.E of the bowling ball right before it hits the ground, K.E = 2450 J
Explanation:
Given data,
The mass of the bowling ball, m = 10 kg
The height of the building, h = 25 m
The total mechanical energy of the body is given by,
E = P.E + K.E
At height 'h' the P.E is maximum and the K.E is zero,
According to the law of conservation of energy, the K.E at the ground before hitting the ground is equal to the P.E at 'h'
Therefore, P.E at 'h'
P.E = mgh
= 10 x 9.8 x 25
= 2450 J
Hence, the K.E of the bowling ball right before it hits the ground, K.E = 2450 J
By previous elements found in other stars, accurate guesses and lots of studying
Answer:
50N
The table is managing to keep the dog up, the dog is not moving up or down so the force that the table applies to the dog must be equal to the dogs weight - I draw this conclusion from Newton's 3rd law.
W= mg
W = 5 × 9.8
W = 49N
round to.one significant figure = 50N
