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3 years ago

What is the temperature shown on the thermometer below?

Physics

1 answer:

erik [133]3 years ago

7 0

Answer:

D, -8 F

Explanation:

This specific thermometer is in increments of two degrees per minor line and 10 per thicker line. Since the thermometer is showing below zero, the answer cannot be A or B since they are positive. -4 Cannot be the answer since the line addition does not make sense for that. It would be -4 if the thick line increments were 5 degrees instead of ten. Therefore if you count the lines by two from zero down to the thermometer line, you would get -8 Degrees F

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DanielleElmas [232]

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4 years ago

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Irina-Kira [14]

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3 years ago

PLEASE HELP ASAP...TIMED TEST. PLEASE ANSWER WITH AT LEAST A PARAGRAPH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

charle [14.2K]

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3 years ago

A certain geothermal power station has a power output of 200,000W.

Ne4ueva [31]

Answer:4800 kWh

Explanation:

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5 0

3 years ago

A wheel 33 cm in diameter accelerates uniformly from 240 rpm to 360 rpm in 6.5 s. how far will a point on the edge of the wheel

melisa1 [442]

First we find the angular acceleration $\alpha$ . The angular velocities are $\frac{240}{60} =4 \;rps$ and $\frac{360}{60} =6 \;rps$ The angular velocities and $\alpha$ are related as

$\omega=\omega_0+\alpha t\\ \alpha =\frac{\omega - \omega_0}{t} \\ \alpha =\frac{6-4}{(6.5)} \\ \alpha =0.3077 \;rps^2\\ \alpha =(0.3077 )2\pi =1.933 \;rad/s^2$

Angle turned in 6.5 seconds is

$2 \alpha\theta = \omega^2-\omega_0^2\\ \theta = \frac{ \omega^2-\omega_0^2}{2 \alpha}\\ \theta = \frac{ 6^2-4^2}{2 (1.933)}\\ \theta = 5.173 \; rad$

The distance traveled by a point on the edge of the wheel is $r \theta = \frac{33}{2}(5.173)= 85.35 \;cm$

7 0

3 years ago