Two identical charged pith balls are brought together to touch each other. They are then
1 answer:
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Answer:
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Explanation:
A vehicle crash problem must be solved with the equation of the moment,
Initial instant Before crash
p₀ = m v₁ + mv₂
After the crash
= m
+ m
p₀ =
If the speed ratio before and after the crash is one
p₀ / = 1
We can assume that initially one of the cars was stopped
m v₁₀ = m
v₁₀ =
For the two speeds to be equal, the masses of the vehicles must be the same.
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
a) ,
The work done by the student in each trial is equal to the gravitational potential energy gained by the student:
where
m = 68 kg is the mass of the student
g = 9.8 m/s^2 is the acceleration of gravity
is the gain in height of the student
For the first student, , so the work done is
The second student runs up to the same height (3.5 m), so the work done by the second student is the same:
2) ,
The power exerted by each student is given by
where
W is the work done
t is the time taken
For the first student, and
, so the power exerted is
For the second student, and
, so the power exerted is