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prisoha [69]
3 years ago
12

Which feature forms as a result of a tectonic plate boundary that creates an underwater mountain range in the open ocean?

Chemistry
2 answers:
Ede4ka [16]3 years ago
6 0

Answer:

NO it Trench you got to believe me

Explanation:

stellarik [79]3 years ago
5 0
This is a mid ocean ridge.
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Question 8 of 10
olga nikolaevna [1]

Answer:

C. 1:30

Explanation:

The toy car is .5 feet long and the actual car is 15 feet long

This gives you a ratio of

.5:15

Now for everything you have to remember this

.5:15

=1:30

=2:45

=3:60

C is the only answer that matches any of the ratios above.

Even if you went farther in the ratios none of them would match this ratio.

Hope this helped.

=)

3 0
3 years ago
The [H3O+] of a solution is 2.5 x10-7. What is the pOH of the solution?
xz_007 [3.2K]

Answer:

7.4.

Explanation:

∵ pH = -log[H₃O⁺].

∴ pH = -log(2.5 x 10⁻⁷) = 6.6.

<em>∵ pH + pOH = 14.</em>

<em />

∴ pOH = 14.0 - pH = 14.0 - 6.6 = 7.4.

6 0
4 years ago
What is the mass of the solute in 250 mL of 0.122 mol/L potassium phosphate?
inysia [295]

Answer:

What is the mass of solute, in grams, in 250.00 mL of a 0.0125 M solution of KMnO4? Moles KMnO4 = M × V = 0.0125 M × 0.250 L = 3.13 × 10-3 mol KMnO4 grams KMnO4 = 3.13 × 10-3 mol KMnO4 × ( 158.03 g KMnO4/1 mol KMnO4) = 0.495 g 4.

8 0
3 years ago
Why can metals be extracted using carbon
8090 [49]
If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
5 0
2 years ago
The freezing point of water H2O is 0.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is urea. If 13.
Trava [24]

Answer:

Molality = 1.46 molal

The freezing point of the solution = -2.72 °C

Explanation:

Step 1: Data given

The freezing point of water H2O is 0.00°C at 1 atmosphere

urea = nonelectrolyte = van't Hoff factor = 1

Mass urea = 13.40 grams

Molar mass urea = 60.1 g/mol

Mass of water = 153.2 grams

Molar mass H2O = 18.02 g/mol

Kf = 1.86 °C/m

Step 2: Calculate moles urea

Moles urea = mass urea /molar mass urea

Moles urea = 13.40 grams / 60.1 g/mol

Moles urea = 0.223 moles

Step 3: Calculate the molality

Molality = moles urea / mass water

Molality = 0.223 moles / 0.1532 kg

Molality = 1.46 molal

Step 4: Calculate the freezing point of the solution

ΔT = i * Kf * m

ΔT = 1* 1.86 °C/m * 1.46 m

ΔT = 2.72 °C

The freezing point = -2.72 °C

3 0
3 years ago
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