Answer:
The fractional saturation for hemoglobin is 0.86
Explanation:
The fractional saturation for hemoglobin can be calculated using the formula
Where is the fractional oxygen saturation
is the partial pressure of oxygen
is the partial pressure when 50% hemoglobin is saturated with oxygen
and h is the Hill coefficient
From the question,
= 40 mm Hg
= 22 mm Hg
h = 3
Putting these values into the equation, we get
Hence, the fractional saturation for hemoglobin is 0.86.
Answer:
19 because it gained 3 electron so 12-3=9 beryllium
2
3 is 46-2=44
4 is 2
5 is 5
6 84 polonium
7
8 oxygen
Explanation:
plz let me know if they are right or wrong:)
Answer:
Reaction
Explanation:
A reaction that is spontaneous at low temperature
<h3>
Answer:</h3>
1031.4 Calories.
<h3>
Explanation:</h3>
We are given;
Mass of the copper metal = 50.0 g
Initial temperature = 21.0 °C
Final temperature, = 75°C
Change in temperature = 54°C
Specific heat capacity of copper = 0.382 Cal/g°C
We are required to calculate the amount of heat in calories required to raise the temperature of the copper metal;
Quantity of heat is given by the formula,
Q = Mass × specific heat capacity × change in temperature
= 50.0 g × 0.382 Cal/g°C × 54 °C
= 1031.4 Calories
Thus, the amount of heat energy required is 1031.4 Calories.
Answer:
A is correct
Explanation:
B speaks of the skeletal system
C speaks of the respiratory system
D speaks of the thoracic cavity and respiratory system
- Hope that helps! Please let me know if you need further explanation.