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DaniilM [7]
2 years ago
14

solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and

businesses through the electric grid are called ________.
Physics
1 answer:
steposvetlana [31]2 years ago
8 0

Concentrated solar power facilities are solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid .

<h3>What is solar power?</h3>

Solar power refer to electric power or electricity that is generated from sun rays or radiations while using solar panels and other technologies.

Therefore, Concentrated solar power facilities solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid.

Learn more about solar power below

brainly.com/question/17711999

#SPJ12

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Answer:

This is the answer bro hope it will help you

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3 years ago
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The formula for calculating power is work divided by time (power = work ÷ time). What are two ways of stating the same relations
nirvana33 [79]
I think they just want you to rewrite it two other ways:

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The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
An automobile with an initial speed of 4.92 m/s accelerates uniformly at the rate of 3.2 m/s2 . Find the final speed of the car
Rudik [331]

Answer:19.32 m/s

Explanation:

Given

initial speed of car(u)=4.92 m/s

acceleration(a)=3.2 m/s^2

Speed of car after 4.5 s

using equation of motion

v=u+at

v=4.92+3.2\times 4.5=4.92+14.4

v=19.32 m/s

Displacement of the car after 4.5 s

v^2-u^2=2as

19.32^2-4.92^2=2\times 3.2\times s

349.05=2\times 3.2\times s

s=54.54 m

4 0
3 years ago
Suppose you are walking in an airliner in flight. Use Newton’s third law to describe the effect of your walk on the motion on th
Novosadov [1.4K]

Answer:

The effect of your walking will create a force on the airline acting downwards, due to the weight. By Newton's thirds law the airline will exert an equal and opposite reaction force directed downwards.

Explanation:

The weight of all the passengers acts downwards on the floor of the Airplane.

The Airplane exerts an equal and opposite force on the passengers, with the help of its propulsion due to which the flight keeps on flying without falling down.

Hence by changing the frame of reference we can observe the force which is responsible for the reaction.

4 0
2 years ago
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