Under what circumstances will the distance traveled by an object be the same as the magnitude of the displacement of an object?

A dragster going at 15 m/s increases its velocity to 25 m/s in in 2 seconds. What is its acceleration?

Strike441 [17]

Answer:

5m/s²

Explanation:

Given parameters:

Initial velocity = 15m/s

Final velocity = 25m/s

Time taken = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time taken. It is mathematically expressed as;

Acceleration = $\frac{Final velocity - Initial velocity }{Time taken }$

Acceleration = $\frac{25 - 15}{2}$ = 5m/s²

8 0

3 years ago

A truck is subject to a drag force, Fd, from the surrounding air: where Cd = 0.28 is the drag coefficient, A = 30 ft2 is the are

denis-greek [22]

Answer:

Power is 15.41 hp

Work is 39205.18 Btu

Explanation:

The power to overcome the drag force is given by the formula:

P = (1/2)ρ v³ A Cd

where,

P = Power

ρ = Density of air = 0.075 lbm/ft³

v = speed of truck = (65 miles/hr)(1 hr/3600 s)(5280 ft/1 mile) = 95.33 ft/s

A = Area = 30 ft²

Cd = drag coefficient = 0.28

therefore,

P = (1/2)(0.075 lbm/ft³)(95.33 ft/s)³(30 ft²)(0.28)

P = (272926 ft².lbm/s³)(1 lbf/32.2 lbm.ft/s²)

P = (8476 ft. lbf/s)(1 hp/550 ft.lb/s)

Now, for the work of 1 hour:

Work = W = P x time

W = (15.41 hp)(2544 Btu/h / 1 hp)(1 h)

6 0

3 years ago

Read 2 more answers

A 6 kg brick is pulled across the flat sidewalk by a horizontal force of 35 N. The brick is experiencing a frictional

SIZIF [17.4K]

<h3>Answer: Approximately 4.67 m/s^2</h3>

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Explanation:

Let's say you want to push the brick to the right. The free body diagram will have an arrow pointing right on the rectangle (the brick) and the arrow is labeled with 35 N.

Friction always counteracts whatever force you apply. The friction force arrow will point left and be labeled with 7 N.

The net horizontal force is therefore 35-7 = 28 N and the direction is to the right. The positive net force means you've overcome the force of friction and the brick is moving.

F = 28 is the net force

m = 6 is the mass

a = unknown acceleration

F = m*a .... newton's second law

28 = 6a

6a = 28

a = 28/6

a = 4.67

The acceleration of the brick is approximately 4.67 m/s^2

This means that for every second, the brick's velocity is increasing by about 4.67 m/s.

6 0

3 years ago

Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls

Dmitrij [34]

Answer:

$(a) 189.23 N$ , $(b) 47.31 N$ and $(c) 141.92 N$ .

Explanation:

Three balls are shown in figure having charge $q=1.45 \mu C$ . The middle ball, $B$ , is positively charged having charge $+q$ , and the remaining two outside balls, $A$ and $C$ , are negatively charged having charged $-q$ as shown.