The tralational equilibrium condition allows finding that the electric potential is V = 4.8 10¹¹ V
Given parameter
- The mass m = 1.5 g = 1.15 10-3 kg
- The charge on the sphere q = 8.9 10-16 C
- Plate spacing d = 5 cm = 5.00 10-2 m
To find
Newton's second law states that the force is proportional to the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it establishes the condition for the equilibrium of the bodies
∑ F = 0
Where the bold indicate vector and F is the force
To use this equation we must fix a reference system with respect to which to carry out the decomposition and measurements of the forces; let's fix a system with the horizontal x axis and the vertical y axis, in the attachment I could see a free body diagram.
x- axis
Fe - Tₓ = 0
Fe = Tₓ
y-axis
- W = 0
W =
mg =
The electric force is
Fe = q E = q V / d
let's use trigonometry to decompose the stress
cos 30 = / T
sin 30 = Tₓ / T
= T cos 30
Tₓ = T sin 30
We substitute
q V / d = T sin 30
mg = T cos 30
It's solve the system of equations
= tan 30
V =
It's calculate
V =
V = 4.768 10¹¹ V
In conclusion, using the equilibrium condition, we could find that the electric potential is V = 4.8 10¹¹ V
Learn more about equilibrium condition here:
brainly.com/question/1967702
Answer:
<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>
Explanation:
The image is shown below.
The force on the particle with charge q due to each charge Q =
we designate this force as N
Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.
Resolving the forces on the particle, we have
for the x-component
= N cosine 60° + (-N cosine 60°) = 0
for the y-component
= -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N
The above indicates that there is no resultant force in the x-axis, since it is equal to zero ( = 0).
The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.
<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>
The net force! That would be the total force off all the forces acting on an object. :)
B show the potential energy and the kenetic energy