What is the value the 1 in 214,278,216

What is the answer please help no links I will report

Hoochie [10]

Answer:

links.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Suppose monthly rental prices for a one-bedroom apartment in a large city has a distribution that is skewed to the right with a

omeli [17]

Answer:

a) Nothing, beause the distribution of the monthly rental prices are not normal.

b) 1.43% probability that the sample mean rent price will be greater than $900

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

(a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930?

Nothing, beause the distribution of the monthly rental prices are not normal.

(b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?

Now we can apply the Central Limit Theorem.

$\mu = 880, \sigma = 50, n = 30, s = \frac{50}{\sqrt{30}} = 9.1287$

This probability is 1 subtracted by the pvalue of Z when X = 900.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{900 - 880}{9.1287}$

$Z = 2.19$

$Z = 2.19$ has a pvalue of 0.9857

1 - 0.9857 = 0.0143

1.43% probability that the sample mean rent price will be greater than $900

8 0

3 years ago

Drag each expression to show whether the product is less than 1

barxatty [35]

Equal to 1:

$3*\frac{1}{3}\ \ , \ \ 5*\frac{1}{5}\ \ , \ \6*\frac{1}{6}$

Less than 1:

$1*\frac{5}{6}$

Greater than 1:

$2 * \frac{3}{4} \ \ , \ \ \ 3 * \frac{2}{5}$

Step-by-step explanation:

We will solve each product one by one.

So,

$3*\frac{1}{3} = 1\\\\6*\frac{1}{6} = 1\\\\2 * \frac{3}{4} = \frac{3}{2}\\\\1*\frac{5}{6} = \frac{5}{6}\\\\3*\frac{2}{5} = \frac{6}{5}\\\\5*\frac{1}{5} = \frac{1}{5}$

As we have all the answers now.

If the denominator of a fraction is greater than ts numerator then the result is less than 1
If the denominator of a fraction is less than its numerator then the result is greater than 1.

So,

Equal to 1:

$3*\frac{1}{3}\ \ , \ \ 5*\frac{1}{5}\ \ , \ \6*\frac{1}{6}$

Less than 1:

$1*\frac{5}{6}$

Greater than 1:

$2 * \frac{3}{4} \ \ , \ \ \ 3 * \frac{2}{5}$

Keywords: Fractions, decimals

Learn more about fractions at:

#LearnwithBrainly

3 0

3 years ago

0.00592 to 4 decimal places

Leya [2.2K]

0.00592 ≈ 0.0059 to 4 decimal places.

The number after the fourth decimal place is 2, and this is not up to 5, so we round down.

6 0

3 years ago

Read 2 more answers

Which transformation would not carry a square onto itself?

Helga [31]

Answer:

Translation because translation is sliding an object.

7 0

4 years ago