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VMariaS [17]
2 years ago
12

What is the molarity of a solution which contains 0.80 mol of HCl in 250mL of solution?

Chemistry
1 answer:
mariarad [96]2 years ago
6 0

Answer:

3.2M HCl Solution

Explanation:

Molarity = moles of solute / volume of solution expressed in liters

moles of solute = 0.80 moles HCl

volume of solution = 250 ml = 0.250 Liter

Molarity (M) = 0.80 moles HCl / 0.250 Liters = 3.2M HCl Solution

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In order to determine the mole ratio, you need to begin with a balanced chemical equation.

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What do we mean by basic MgO?
aliina [53]

Answer:

Magnesium oxide is a simple basic oxide, because it contains oxide ions. It reacts with water to form magnesium hydroxide which is a base.

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2 years ago
HELP PLZ ASAP I NEED IT and no links plz ANd Plz HURRRRRy
mars1129 [50]

<u>Answer:</u> The balanced chemical equation is 2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

<u>Explanation:</u>

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation:

KClO_3(s)\rightarrow KCl(s)+O_2(g)

<u>On the reactant side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 3

<u>On the product side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 2

To balance the equation, we must balance the atoms by adding 2 infront of both KClO_3(s) and KCl(s). Also, a coefficient of 3 must be written infront of O_2(g)

For the balanced chemical equation:

2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

5 0
3 years ago
A 45.0 g sample of a metal at 85.6 °C is placed in 150.0 g of water at 24.6 °C. The final temperature of the system is 28.3 °
earnstyle [38]

Answer:

904.014 j/kgk

Explanation:

Mass of metal = 45g

Temperature of metal = 85.6°

Mass of water = 150

Temperature of water = 24.6

Final temperature of system = 28.3

Heat lost by metal = Heat gained by water

m1 * c1 * dt = m2 * c2 * dt

Q = quantity of heat

Q = m*c*dt

dt = change in temperature

dt of water = 28.3 - 24.6 = 3.7

dt of metal = 85.6 - 28.3 = 57.3

Specific heat capacity of water, c = 4200

(45 * 10^-3) * c * 57.3 = (150 * 10^-3) * 4200 * 3.7

2.5785c1 = 2331

c1 = 2331 / 2.5785

= 904.01396

= 904.014 j/kgk

3 0
2 years ago
Chemistry Conversion
kvv77 [185]

Answer:

Explanation:

193.02 times 9.55 it's going to be 1843.341

9.55= 191.20 milli

4 0
3 years ago
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