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erica [24]
3 years ago
8

Consider the data collected in science class. Different masses were thrown with varied amounts of

Physics
2 answers:
hichkok12 [17]3 years ago
6 0

Answer:

a. in all cases, the acceleration was the same

Explanation:

Do the math - F = ma. In each case, the acceleration is 5 m/s2.

lesya [120]3 years ago
4 0

Answer:

A: In all cases, the acceleration was the same.

Explanation:

I know this because its a clear obvious answer not only that it was one of my USA TESTPREP questions and it was right.

All you mainly have to do is the math - F=ma , In each case , the acceleration is 5 m/s squared

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A car travels 480 km in 12 hr. what is its velocity
Svet_ta [14]

Answer:

Explanation:

velocity=s/t

given distance is 480 km we have to convert it into meter because the unit of distance is meter

1 km=1000 m

480 km=480000 m =4.8*10^5

1 hour= 3600 s

12 hour =43200 s  

now velocity=s/t

v=4.8*10^5/43200

v=11.11 m/s

5 0
3 years ago
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Describe two rights and two responsibilities that you have as an employee
Pachacha [2.7K]
As an employee you have the right to receive money but the responsability to work as your advisor ask you for
as an employee you have the right to work safety but the responsability to do all is accept ,and respectul by that way you can save your life and other by the same time

i can give you a last exemple

as an employee you have the right to have holyday break because you also need to be with your family but the responsability to stay in work when you have to
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A squirrel jumps into the air with a velocity of 4 m/s at an angel of 50 degrees. What is the maximum height reached by the squi
Debora [2.8K]

Answer:

Explanation:

Assuming the squirrel is jumping off the ground, here's what we know but don't really know...

v₀ = 4.0 at 50.0°

So that's not really the velocity we are looking for. We are dealing with a max height problem, which is a y-dimension thing. Therefore, we need the squirrel's upward velocity, which is NOT 4.0 m/s. We find it in the following way:

v_{0y}=4.0sin(50.0) which gives us that the upward velocity is

v₀ = 3.1 m/s

Moving on here's what we also know:

a = -9.8 m/s/s and

v = 0

Remember that at the very top of the parabolic path, the final velocity is 0. In order to find the max height of the squirrel, we need to know how long it took him to get there. We are using 2 of our 3 one-dimensional equations in this problem. To find time:

v = v₀ + at and filling in:

0 = 3.1 - 9.8t and

-3.1 = -9.8t so

t = .32 seconds.

Now that we know how long it took him to get to the max height, we use that in our next one-dimensional equation:

Δx = v_0t+\frac{1}{2}at^2 and filling in:

Δx = 3.1(.32)+\frac{1}{2}(-9.8)(.32)^2 and using the rules for adding and subtracting sig fig's correctly, we can begin to simplify this:

Δx = .99 - .50 so

Δx = .49 meters

7 0
3 years ago
The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4
scoundrel [369]

The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:

a)  we have four sections;

  • 0 to 8 s The body is accelerating.
  • 8 to 10 s The body goes at a constant speed, the acceleration is zero.
  • 10 to 14 Body accelerating.
  • 14 to 18 Body slowing down.

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  d_{total}= 16 m

e) maximum speed  is:      v = 6 m / s

Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.

        v = v₀ + a t

        y = v₀ t + ½ a t²

where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.

In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:

  • Positive slope the body is accelerating and the speed is increasing.
  • Negative slope the body is stopping, the speed decreases.

Let's answer the different questions about the system.

a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;

  • 0 to 8 s The body is accelerating.
  • 8 to 10 s The body goes at a constant speed, the acceleration is zero.
  • 10 to 14 Body accelerating.
  • 14 to 18 Body slowing down.

b) The acceleration is the first 8 s

          v = v₀ + a t

          a = \frac{v-v_o}{\Delta t}  

          a = \frac{2-0}{8-0}  

          a = 0.25 m / s²

c) The maximum acceleration is when the slope is maximum.

          a = \frac{6-2}{ 14-10}  

          a = 1 m / s²

Therefore the acceleration is maximum in the section between 10 and 14 s

d) The total displacement is the sum of the displacements of each section.

         d_{total } = d_1 +d_2 + d_3 +d_4  

We look for every displacement.

       d₁ = v₀ + ½ a₁ Δt²

       d₁ = 0 + ½ 0.25 8²

       d₁ = 8 m

In the second section the velocity is constant

         d₂ = v₂ Δt₂

         d₂ = 2 (10-8)

         d₂ = 4 m

The third section.

    d₃ = v₀ + ½ a t²

    d₃ = 2 + ½ 1 (14-10) ²

    d₃ = 10 m

The distance of the fourth section.

       

we look for acceleration

          a₄ = \frac{v-v_o}{\Delta t}  

          a₄ = \frac{0-6}{18-14}  

          a₄ = -1.5 m / s²

     

          d₄ = 6 + ½ (-1.5) (1814) ²

          d₄ = -6 m

The total displacement is;

          d_{total} = 8 + 4 + 10 -6

          d_{total} = 16 m

e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to

          v = 6 m / s

In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:

  a)  we have four sections;

  • 0 to 8 s The body is accelerating.
  • 8 to 10 s The body goes at a constant speed, the acceleration is zero.
  • 10 to 14 Body accelerating.
  • 14 to 18 Body slowing down.

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  d_{total}= 16 m

e) maximum speed  is:      v = 6 m / s

Learn more about kinematics here: brainly.com/question/24783036

3 0
2 years ago
I will GIVE BRAINLYEST AND POINTS PLEAS HELP!!!
Elenna [48]

Answer:

1. Sports education-uses seasons and teams to educate

2. Adventure education-uses challenging recreational activities

3. Outdoor education-may use camps to teach activities

4. Dance education-uses cultural movement activities

5. fitness education-teaches concepts and self-management skills

Explanation:

I figured that these answers made the most sense so ya.

3 0
3 years ago
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