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Olegator [25]
3 years ago
6

Please Please Please Help Me In These Physics Questions!!!!!!!!!!!!!!!! ASAP!!!!!!!!

Physics
1 answer:
Ainat [17]3 years ago
5 0
#11: Impulse(I)=FΔt; Δt=T final - T initial/or rather given time
                       =4.16×10⁻⁴(1.84×10⁶)
<span>                       =7.65×10²Ns
</span>#12: Spring Force(F)=kx; k-spring constant
                                         x-extension
by making k subject of the formula:
<span>spring constant(k)=F/x
</span>  =3.92×10²/3.84×10⁻³
<span>                             =1.02×10*5N/m
</span>#13: Spring potential(U)= 1/2 kx²
                                      = 1/2(9.33×10³)(4.95×10⁻²)²
<span>                                      =1.14×10*1J
#14: Centripetal Force(Fc)=m(v²/r)
<span>                                          =ma; v²/r=a
</span>
         making m subject of formula:
                                       m=Fc/a
                                          =7.56×10³/6.14×10*-1
<span>                                          =1.23×10*4kg
</span></span>#15: From definition of Fc, it can be noted that acceleration a=v²/r
        making v(speed) subject of formula;
<span>                                         v=√ar
</span>                                           =√4.92×10⁻¹ (2.43×10¹)
<span>                                           =3.46×10*0m/s           

Hope this helps!</span>                               
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Answer:

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Explanation:

Hi there!

The equation of the horizontal position of the cork in function of time is the following:

x = x0 + v0 · t · cos θ

Where:

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If we place the origin of the frame of reference at the launching point, then x0 = 0.

We know that at t = 1.25 s, x = 1.50 m. We also know the launching angle so we can solve the equation of horizontal position for the initial speed, v0:

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Explanation:

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