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BigorU [14]
3 years ago
11

Imagine you re in an entrepreneur and have been provided a loan by a bank to set up a small electro plating unit. What would you

like to electorate and for what purpose?
Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:

Electroplating involves deposition of a thin layer of metal onto the surface of a substance(compound) through electric current. This helps preserve the substance(compound) from rust and oxidative damage.

As an entrepreneur which has been provided a loan by a bank to set up a small electro plating unit. I would venture into electroplating electronic/electric appliances parts.This is because these types of appliances are in vogue now and used my millions of people for their day to day activities. This means that more people will come for various degrees of production and repairs which would include electroplating . This translates to more customers and more money for the repayment of the loan.

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How many atoms of oxygen are there in one molecule of trinitrotoluene, if the chemical formula is C6H3(NO2)3?
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2 x 3 = 6

Thus there are 6 atoms of oxygen in this molecule.

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The heat flows into my body and I start with a warming feeling going down my throat as it starts there I get this warm feeling and I break out in a coldsweat from consuming a warm drink a cold drink will help cool me down :

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If drink warm will make u warm drinking cool will make u cool down faster

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0.0025H

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Pressure of gas is 13.6 cm of hg what does it means​
vlada-n [284]

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An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra
slega [8]

Answer:

Part a)

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

E = 4.4 \times 10^{-13} J

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

m_1v_1 + m_2v_2 + m_3v_3 = 0

(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0

(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

By equation of kinetic energy we have

E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2

E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}

E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}

E = 4.4 \times 10^{-13} J

8 0
3 years ago
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