Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?

Physics

1 answer:

Pavel [41]2 years ago

3 0

The problem is missing some parts but nevertheless here is the answer:

Given:

1.7 m long barbell with 23 kg weight on the left and 34 in the right end.

Solution:

Calculating from the left side:

Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34]

Center of gravity = .992 m from the left end

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6. During an impact time casting 5 x 10-45 a gulf club exerts an average impar

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