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N76 [4]
3 years ago
10

Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?

Physics
1 answer:
Pavel [41]3 years ago
3 0

The problem is missing some parts but nevertheless here is the answer:

 

Given:

1.7 m long barbell with 23 kg weight on the left and 34 in the right end.

 

Solution:

 Calculating from the left side:

Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34] 

Center of gravity = .992 m from the left end

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mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

       Em₀ = U = m g y

Lowest point

     Em_{f} = K = ½ m v²

As there is no friction, mechanical energy is conserved

       Em₀ = Em_{f}

       m g y = ½ m v²

       v = √ 2 g y

Where we can use trigonometry to find and

       sin 30 = y / L

       y = L sin 30

Let's replace

      v = RA (2 g L sin 30)

Let's calculate

      v = RA (2 9.8 100.0 sin30)

      v = 31.3 m / s

4 0
2 years ago
You are driving your car at a speed of 60 miles per hour, when you cross into Canada. Canada measures their speed in kilometers
Flauer [41]

Answer:

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I don't know

Explanation:

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8 0
3 years ago
A motorbike travels 45 miles in 15 minutes, what is its speed (hint change the minutes to hours!!)
Flauer [41]

Answer:

180 miles/hr

Explanation:

15 min=1/4 hr

s= distance/time

s=45miles/1/4 hr

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6 0
3 years ago
Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths f
Bogdan [553]

Answer:

the minimum wall thickness that will enhance the reflection of light is 146.9 nm

Explanation:

Given the data in the question;

At the first interface, a phase shift occurs as the incident light is in air that has less refractive index compare to the thin film of soap bubble.

At the second interface, no shift occurs,

condition for constructive interference;

t = ( m + 1/2) × λ/2n

where m = 0, 1, 2, 3 . . . . . .

now, the condition for the constructive interference;

t = mλ/2n

where t is the thickness of the soap bubble,  λ is the wavelength of light and n is the refractive index of soap bubble.

so the minimum thickness of the film which will enhance reflection of light will be;

t_{min =  ( m + 1/2) × λ/2n

we substitute

t_{min =  ( 0 + 1/2) × 711 /2(1.21)

t_{min = 0.5 × 711/2.42

t_{min = 0.5 × 293.80165

t_{min = 146.9 nm

Therefore,  the minimum wall thickness that will enhance the reflection of light is 146.9 nm

8 0
2 years ago
The frequency of light emitted from a source is changed. What visible evidence would indicate this?
Llana [10]
The change of color. Each color has a different wavelength therefore a different frequency.
5 0
3 years ago
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