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N76 [4]
3 years ago
10

Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?

Physics
1 answer:
Pavel [41]3 years ago
3 0

The problem is missing some parts but nevertheless here is the answer:

 

Given:

1.7 m long barbell with 23 kg weight on the left and 34 in the right end.

 

Solution:

 Calculating from the left side:

Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34] 

Center of gravity = .992 m from the left end

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When Arti kicks a football, two forces interact. Arti's foot exerts a force on the ball. What exerts a force on Arti's foot?
vagabundo [1.1K]
The football and air resistance between contact
7 0
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poizon [28]

Answer:

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Explanation:

3 0
3 years ago
A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
Karolina [17]

Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

Vd = 7.76*10^-5/1.3584*10^10

Vd = 5.71*10^-15

Therefore, the current density and speed drift are 4.9*10^-6

And 5.71*10^-15 respectively

3 0
3 years ago
EASY MATCHING PLEASE HELP!
kakasveta [241]
<h2><u>Answers:</u></h2><h2>1.) Right answer: polarization  </h2>

Alignment of light in only one vibrational orientation: polarization  

Normally, electromagnetic waves (light) are not polarized, so electromagnetic vibration occurs in all planes. But when we get these waves to vibrate in a single plane, we have polarized light.

This is possible because electromagnetic waves are transversal waves, this means the electric field oscillates in all normal directions to the direction of wave propagation.

In other words:

<em>Its oscillation occurs in the transversal direction to its propagation. </em>

So, when polarization occurs the electric field vibrates or oscillates in a given plane, called the <u>polarization plane</u>.

It should be noted that this phenomenon is only possible in transversal waves, in longitudinal waves, such as sound waves, polarization is not possible because its oscillation occurs in the same direction as its propagation.

<h2>2.) Right answer: concave  </h2>

Mirror that causes parallel incident rays of light to converge at the focus: concave  

A concave mirror, or convergent mirror, has a reflective surface that is curved inwards.

The concave mirrors reflect the light making it converge in a focal point therefore they are used to focus the light. This occurs because the light is reflected with different angles, since the normal to the surface varies from one point to another of the mirror.

<h2>3.) Right answer: photoelectric effect </h2>

phenomenon that can be explained only by a particle model for light: photoelectric effect  

Light can be considered as a wave or as particles (photons), in this context the photoelectric effect can only be explained based on the corpuscular model (particles) of light.

Then, the photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.

If the light is a stream of photons and each of them has energy, this energy is be able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.

 

<h2>4.) Right answer: Taylor's experiment   </h2>

experiment that showed that diffraction effects could be attributed to light particles: Taylor's experiment  

This experiment was carried out by Geoffrey Taylor in 1909 with a flame as a light source, a diffraction grating and a photographic plate.

All this to test the diffraction of light.


<h2> 5.) Right answer: reflection  </h2>

principal use of mirrors: reflection

Mirrors fulfill the principle of reflection, which occurs when the light rays fall on a very flat reflecting surface are reflected so that the incident angle is equal to the reflected angle

<h2>6.) Right answer: mirage  </h2>

image of the sky seen on a hot road: mirage

A mirage is the product of an optical illusion due to the total reflection of the light when crossing layers of hot air of different density; this causes the perception of the inverted image of distant objects, as if they were reflected in the water.

<h2>7.) Right answer: virtual  </h2>

type of images always produced by convex  mirrors: virtual

In the convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object.

<h2>8.) Right answer: diffraction  </h2>

pattern produced by light through a narrow slit: diffraction

Diffraction is a phenomenon that is based on the deviation of the waves (light waves in this case) when encountering an obstacle or going through a slit

<h2>9.) Right answer: convex  </h2>

shape of a converging lens: convex  

A convex lens is thicker in the center than at its edges and concentrates (converges) at a point the rays of light that pass through it.

<h2>10.) Right answer: dispersion  </h2>

separating light into component colors: dispersion  

The dispersion of light occurs when a beam of composite light is refracted (the different rays of light are diverted depending on their frequencies) in some medium, leaving their constituent colors separated.

The best known case is when a beam of white light from the sun passes through a prism, thus obtaining rays of different colors like those of the rainbow.


8 0
3 years ago
Read 2 more answers
Help with this physics task pls
cupoosta [38]

Answer:

Answers can be seen below

Explanation:

First we must explain the essential when we clear equations, and that is that if the term we need to clear is accompanied by other terms that are being added up, then those terms go to the other side of the equation to subtract if those terms are subtracting, then they go to the other side to add, if those terms are found multiplying then they go to the other side of the equation to divide and if those other terms are found dividing then they go to the other side of the equation to multiply.

(Primero debemos explicar lo esencial cuando despejamos ecuaciones, y es que si el término que necesitamos despejar va acompañado de otros términos que se están sumando, entonces esos términos van al otro lado de la ecuación para restar si esos términos están restando, luego van al otro lado para sumar, si esos términos se encuentran multiplicando luego van al otro lado de la ecuación a dividir, y si esos términos se encuentran dividiendo, pasan al otro lado de la ecuación a multiplicar.)

1 )  

t=\frac{v}{a} ; d=s*(t-t_{0} )

2)

k=\frac{2*U}{x^{2} }; T_{2}=\frac{P_{2}*V_{2}*T_{1}  }{P_{1}*V_{1}  }  \\

3)

L=\frac{F}{\pi*r*P}; d=\frac{w}{F*cos(o)}

4)

t^{2}=\frac{2*x}{g}  ; V_{2}=\frac{A_{1}*V_{1} }{A_{2} }  \\

5)

h=\frac{V}{\pi *r^{2} } ; r=\frac{t}{F*sin(o)}

6)

h=\frac{m}{(1/2)*\pi *r^{2} }  ; h_{2}=\frac{F_{2}*(1/2)*b_{1} *h_{1} }{F_{1}*(1/2)*b_{2}*h_{2}   }

7)

b=\frac{mg-ma}{v}; m=\frac{F+kx}{g*cos(o)}

8)

a=\frac{v-v_{o} }{t} ; u=\frac{m_{1}+m_{2}  }{M}

9)

v_{o}=\frac{x-\frac{1}{2}*a*t^{2}  }{t}  ; F=\frac{W+uNd}{d*cos(o)}

10)

h=\frac{E-\frac{1}{2}*m*v^{2}  }{mg} ; v_{2} ^{2} = \frac{Dk-\frac{1}{2} m*v_{1}^{2}  }{\frac{1}{2}m }

11)

N=\frac{mg*sin(o)-F}{u} ; x^{2}=\frac{W+\frac{1}{2}k*x_{1}^{2}   }{\frac{1}{2}*k }

12)

x=x_{o} +\frac{v^{2-v_{o}^{2}  } }{2a}  ;  m=\frac{P*A-F_{1}-F_{2} }{g}

13)

x_{o} = x-\frac{F}{k} ;  u=\frac{cos(o)-\frac{a}{g} }{sin(o)}

14)

t=\frac{d}{v} +t_{o} ; t_{o} = t-(\frac{v-v_{o} }{a} )

15)

F_{2}=\frac{W-F_{1} *d}{d}+F_{3}   ;  v_{2}^{2}=v_{1}^{2}+\frac{2*Dk}{m}

16)

y_{1}=y-\frac{u}{mg}  ; x^{2} = \frac{2W}{k}+x_{o} ^{2}

7 0
3 years ago
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