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mojhsa [17]
3 years ago
5

For his senior project, Richard is researching how much money a college graduate can expect to earn based on their major. He fin

ds the following interesting facts:
Basketball superstar Michael Jordan was a geography major at the University of North Carolina.

There were only 3 civil engineering majors from the University of Montana. They all took the exact same job, earning the exact same salary at the same company.

Of the 35 finance majors from Wesleyan University, 32 got high-paying consulting jobs, and the other 3 were unemployed. Which of the following is true?

The standard deviation for incomes of civil engineers from the University of Montana is abnormally low.

(Choice B)
B
There is enough information to compare the mean income for finance majors from Wesleyan with the interquartile range for incomes of geography majors from UNC.

(Choice C)
C
The median income for geography majors from UNC is abnormally high.

(Choice D)
D
The interquartile range and the standard deviation for incomes of civil engineers from the University of Montana are equal.
Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:

The standard deviation for incomes of civil engineers from the University of Montana is abnormally low.

and

The interquartile range and the standard deviation for incomes of civil engineers from the University of Montana are equal.

kicyunya [14]3 years ago
4 0

Answer:

B. The standard deviation for incomes of civil engineers from the University of Montana is abnormally low.

D. The interquartile range and the standard deviation for civil engineers from the University of Montana are equal.

Step-by-step explanation:

A and C are incorrect

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Find the amount of interest earned on $5,000 at 15% compounded annually for 10 years. (Round your answer to the nearest dollar.)
8_murik_8 [283]

Answer:

$7500

Step-by-step explanation:

I=PRT

=5,000×0.15×10

8 0
3 years ago
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Solve the expression below, when x = 8 <br> (x - 4) + 12
LenaWriter [7]

Answer:

16

Step-by-step explanation:

Lets solve this step by step,

First we insert 8 in x's place:

(8 - 4) + 12

Now we solve:

8 - 4 = 4

(4) + 12

4 + 12 = 16

Answer: 16

Hope this Helps

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2 years ago
Help im being timed
Oksanka [162]

Answer:

he made the error in step 2

Step-by-step explanation:

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Suppose an online auction website has roughly 500,000 users, and as each member signs up for an account,he or she is assigned a
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D. Surveying every 500th number
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