I.i = j.j = 1
i.j = j.i = 0
(-2i - 5j)(i -4j)
= (-2i).i + (-2i).(-4j) + (-5j).i + (-5j).(-4j)
= -2 + 0 + 0 + 20 = 18
1/f= 1/di+1/do
1/f=1/90m+1/40m
1/f ≈27.7m
Answer:
A. topsoil the answer
Explanation:
I think its a correct answer
W = Fd
W = 1225 N x 10 m = 12250
Answer:
a) 
b) 
Explanation:
Given:
height of water in one arm of the u-tube, 
a)
Gauge pressure at the water-mercury interface,:

we've the density of the water 


b)
Now the same pressure is balanced by the mercury column in the other arm of the tube:



<u>Now the difference in the column is :</u>


