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rodikova [14]
3 years ago
8

Participating in regular exercise

Physics
1 answer:
sladkih [1.3K]3 years ago
8 0
Common health issues that can be positively affected, prevented or controlled by exercise.
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. (a) How long can you play tennis on the 800 kJ (about 200 kcal) of energy in a candy bar? (b) Does this seem like a long time?
galina1969 [7]

(a). The power of the candy bar is,

P=440\text{ W}

The time taken to play on 800 kJ energy of the candy bar is,

t=\frac{E}{P}

where E is the energy.

Substituting the known values,

\begin{gathered} t=\frac{800\times10^3}{440} \\ t=1.818\times10^3\text{ s} \\ t=1818\text{ seconds} \end{gathered}

As 1 minute is equal to 60 seconds,

Thus,

\begin{gathered} t=1818\text{ seconds} \\ t=\frac{1818}{60} \\ t=30.3\text{ min} \end{gathered}

Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.

(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.

The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.

8 0
1 year ago
Sound travels at a rate of 340 m/s in all directions through air. Matt rings a very loud bell at one location, and Steve hears i
Mice21 [21]
It took 450/340 = 1.32 seconds
5 0
4 years ago
Do deaf children go through the four stages of acquiring language? Use what you’ve read in the chapter to explain why or why not
sdas [7]
No deaf children dont. im deaf and i dident go through those stages.

4 0
4 years ago
N asteroid of mass 58,000 kg carrying a negative charge of 15 μc is 180 m from a second asteroid of mass 52,000 kg carrying a ne
Deffense [45]
For this problem, we use the Coulomb's Law. The working equation is written below:

F = kQ₁Q₂/d²
where 
F is the electric force
k is a constant equal to 8.99 × 10⁹ N • m²/C²
Q is the charges for the two objects
d is he distance between the objects

Substituting the values,
F = (8.99 × 10⁹ N • m²/C²)(-15×10⁻⁶ C)(-11×10⁻⁶ C)/(180²)
F = 4.578×10⁻⁵ N

Next, we determine the gravitational force using the Law of Universal Gravitation:

F = Gm₁m₂/d²
where
F is the gravitational force
G is a constant equal to 6.67 × 10⁻¹¹ N • m²/kg²
m is the masses of the objects
d is the distance between the objects

F = (6.67 × 10⁻¹¹ N • m²/kg²)(58,000 kg)(52,000 kg)/(180²)
F = 6.2089×10⁻⁶ N

The sum of the two forces equal the net force:
Net force = 4.578×10⁻⁵ N + 6.2089×10⁻⁶ N = 1.079×10⁻⁵ N 
6 0
3 years ago
Read 2 more answers
Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h

Next, you calculate the difference between both times t1 and t2:

\Delta t=t_1-t_2=2.30h-1.875h=0.425h

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0
3 years ago
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