Hi there!
We can use the following (derived) equation to solve for the final velocity given height:
vf = √2gh
We can rearrange to solve for height:
vf² = 2gh
vf²/2g = h
Plug in the given values (g = 9.81 m/s²)
(13)²/2(9.81) = 8.614 m
We can calculate time using the equation:
vf = vi + at, where:
vi = initial velocity (since dropped from rest, = 0 m/s)
a = acceleration (in this instance, due to gravity)
Plug in values:
13 = at
13/a = t
13/9.81 = 1.325 sec
Answer:
2.7%
Explanation:
Given:
Uncertainty of the speedometer (u)= 2.5km/h
Speed measured at that uncertainty (v) = 92km/h
Percent uncertainty (p) is given as the ratio of the uncertainty to the speed measured then multiplied by 100%. i.e
p =
%
p =
%
p = 2.7%
Therefore, the percent uncertainty is 2.7%
Answer:
no I don’t think there can be so my answer is No.
Okay then yes sorry that I must have gotten it wrong before.
Explanation:
Acceleration is the
rate of change of velocity, a body moving with uniform velocity does not
possess acceleration at all i.e. acceleration is zero
Answer:
h = 599.5 m
Explanation:
Given,
height of structure = 828 m
weight of the tourist = 184 lb
= 184 x 0.45359 = 83.43 Kg
Potential energy = 187000 J
PE = m gd


h = 228.5 m
Height of the room above the ground.
h = 828 - 228.5
h = 599.5 m
Height of the floor above ground is equal to 599.5 m.