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3 years ago

Please help will mark brainliest.

Physics

2 answers:

Zolol [24]3 years ago

8 0

Answer:C

Explanation:

ludmilkaskok [199]3 years ago

5 0

Answer:

Explanation:

#Nova

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a racing car undergoes a uniform acceleration of 4.00m/s2. if the net force causing the acceleration is 3.00 times 10^3 N, what

yKpoI14uk [10]

Answer: 750Kg

Explanation:

Recall that force is the product of the mass M, of an object moving at a uniform acceleration.

i.e Force = Mass x Acceleration

In this case, Mass = ?

Force = 3.00 x 10^3 N = (3.00 x 1000N)

= 3000N

Uniform acceleration = 4.00m/s^2

Force = Mass x Acceleration

3000N = Mass x 4.00m/s^2

Mass = (3000N/4.00m/s^2)

Mass = 750Kg (The SI unit of mass is kilograms)

Thus, the mass of the car is 750Kg

4 0

3 years ago

If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 6 ov, the current flowing through the circ

Anestetic [448]

The current in the circuit =5 A

Explanation:

Voltage = 60 V

resistance= 12 ohm

using ohm's law V=i R

60= i (12)

i=60/12

i=5 A

Thus the current flowing in the circuit = 5 A

6 0

3 years ago

Why is a force required to keep a body moving with a uniform speed in a circular motion?

andrew-mc [135]

Because if there's no force on the object, then it just moves in a straight line.

6 0

4 years ago

the second question. the answer to the first part is 616. pls i have a 34 on the assignment rn pls help

Marat540 [252]

Answer:

a) Ffloor = 616.56[N]

b) Ffloor = 484.16 [N]

Explanation:

In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.

Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.

ΣF = m*a

where:

F = force [N] (units of Newtons]

m = mass [kg]

a = acceleration [m/s²]

g = gravity acceleration = 9,81 [m/s²]

$F_{floor} -m*g = m*a$

$F_{floor} -(56*9.81)=56*1.2\\F_{floor}= 616.56[N]$

b) Using Newton's second law we have.

$F_{floor}-m*g= -m*a\\F_{floor}=-m*a+m*g\\F_{floor} = -(56*1.2) + (56*9.81)\\F_{floor} = 484.16 [N]$

5 0

3 years ago

Two obiect accumulated a charge of

tamaranim1 [39]

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

$q_1=4.5\mu C=4.5\cdot 10^{-6}C$ is the magnitude of the 1st charge

$q_2=2.8\mu C=2.8\cdot 10^{-6}C$ is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

$F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N$

So, the closest answer is

A) 181.24 N

3 0

4 years ago