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Nadusha1986 [10]
3 years ago
7

PLEASE HELP ME ASAPPPP

Chemistry
1 answer:
kykrilka [37]3 years ago
6 0
27.3gFe*( \frac{1molFe}{55.85gFe} )*( \frac{2molFe2O3}{4molFe} )*( \frac{159.7g Fe2O3}{1mol Fe2O3} ) = 39.03g Fe2O3

79.9gO2*( \frac{1molO2}{32gO2} )*( \frac{2molFe2O3}{3molO2} )*( \frac{159.7g Fe2O3}{1molFe2O3} )= 265.83gFe2O3

265.83gFe2O3-39.03g Fe2O3=226.8g Fe2O3

226.8g Fe2O3 is the answer.
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