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OlgaM077 [116]
3 years ago
9

Why is unit of pressure called a derived unit ?? 2) how do you measure the volume of milk?​

Chemistry
1 answer:
trasher [3.6K]3 years ago
4 0

1. Unit of pressure called a derived unit because it is a combination of base units (kg·m^-1·s^·2).

2. We measure the volume of milk by a instrument called Milk Lactometer.

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If the pressure inside the cylinder increases to 1.3 atm, what is the final
EleoNora [17]

Answer:

1.4 × 10² mL

Explanation:

There is some info missing. I looked at the question online.

<em>The air in a cylinder with a piston has a volume of 215 mL and a pressure of 625 mmHg. If the pressure inside the cylinder increases to 1.3 atm, what is the final volume, in milliliters, of the cylinder?</em>

Step 1: Given data

  • Initial volume (V₁): 215 mL
  • Initial pressure (P₁): 625 mmHg
  • Final volume (V₂): ?
  • Final pressure (P₂): 1.3 atm

Step 2: Convert 625 mmHg to atm

We will use the conversion factor 1 atm = 760 mmHg.

625 mmHg × 1 atm/760 mmHg = 0.822 atm

Step 3: Calculate the final volume of the air

Assuming constant temperature and ideal behavior, we can calculate the final volume of the air using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 0.822 atm × 215 mL / 1.3 atm = 1.4 × 10² mL

5 0
3 years ago
What are the main ways that carbon dioxide enter the atmosphere?
BaLLatris [955]
Photosynethesis, respiration, and combustion.
 
7 0
3 years ago
Approximately how many natural forming elements are there
mamaluj [8]
98 elements are naturally forming elements.

Answer: 98
3 0
3 years ago
Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge
zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

brainly.com/question/14044066

#SPJ1

5 0
2 years ago
What is the pOH of a base with a OH- concentration of 0.0500 x 10-11 M? PLEASEEEEEE ASAP
Ksivusya [100]

Answer:

poH= -log(oh^-)

= - log (0.500* 10^-11)

= =- log 0.5 + log (10^-11)

= -( -0.30 +(-11))

=+ 11.3

4 0
3 years ago
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