In this problem we will apply Boyle's Law. According to this law, there is a inverse relation between volume and pressure. As the presseure is being increased in this problem so the volume should be less than the initial volume. Solution is as follow,
Answer:
5.64x10⁻³ g of S₈S₈
Explanation:
We consider mm as milimolal
Milimolal = molal . 1000
Molal are the moles of solute contained in 1kg of solvent.
Solute → Sulfur (S₈S₈)
Solvent → naphthalene
0.11 mm / 1000 = 1.1x10⁻⁴ molal
moles of solute / kg of solvent = 1.1x10⁻⁴ molal
moles of solute / 0.1 kg of solvent = 1.1x10⁻⁴ molal
moles of solute = 1.1x10⁻⁴ m/kg . 0.1kg → 1.1ₓ10⁻⁵ moles
Molar mass S₈S₈ = 512.96 g/m
1.1ₓ10⁻⁵ mol . 512.96 g/m = 5.64x10⁻³ g
The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
<h3>How to find the mass of solute ? </h3>
Mass of solute = Mass percent of solute x Mass of the solution
Here,
Mass percent of solute = 18.7 %
Mass of the solution = 27.2 kg
Now put the value in above formula we get
Mass of solute = Mass percent of solute x Mass of the solution
= 
= 
= 5.086
Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
Learn more about the Mass Percent here: brainly.com/question/26150306
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Answer:
1.20 × 10⁻³ mol e⁻
Explanation:
There is some info missing. I think this is the original question.
<em>Suppose a current of 0.880 A flows through a copper wire for 132 seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.</em>
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Step 1: Given data
- Intensity of the current (I): 0.880 A (= 0.880 C/s)
Step 2: Calculate the charge, in Coulomb, that travel through the wire
We will find the circulating charge (q) using the following expression.

Step 3: Calculate the moles of electrons with a charge of 116 C
We will use the relationship 1 mole of electrons = 96,486 C (<em>Faraday's constant</em>)
