<u>Answer:</u> The molarity of KOH is 0.84 M.
<u>Explanation:</u>
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given
Putting values in above equation, we get:
Hence, the molarity of KOH is 0.84 M.
Answer:
1. In electron dot structure, the dot represent one electrons.
2. Ionic compounds are highly soluble in water.
3. The bond formed by the mutual sharing of two electrons is called covalent bond.
4. there are 3 bonds in nitrogen molecule.
5. the ionic bonds are non-directional.
6. NaCl is taken in molten state
7. formula of common salt is NaCl.
8. Oxygen gas is a diamotic molecule.
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Answer:
astrioids can be found at the astrioid belt
Answer:
Dimer of two peptide chains with 1 mole of molybdenum metal each.
Explanation:
Percentage of molybdenum in protein = 0.08%
Molecular mass of nitrate reductase = 240,000 g
Mass of molybdenum = x
Moles of molybdenum =
Each peptide chain of nitrate reductase contain 1 mole of molybdenum.
This means that nitrate reductase is composed of to two peptide chains. And in each peptide there is a single mole of molybdenum metal.
Answer: 3.59
Explanation:
(2.06)(1.743)(1.00)
2.06 × 1.743 × 1.00
= 3.59058
Two of the multiplied digits are represented in 3 significant figures. Therefore, for correct representation, the result of the product should be written to three significant figures.
3.59058 to 3 significant figures:
First three digits = 3.59
Fourth digit '0' is less than 5, and thus rounded to 0 with other succeeding digits
Therefore, (2.06)(1.743)(1.00) to 3 significant figures equals :
3.59
