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Maslowich
2 years ago
12

Select all that apply.

Chemistry
1 answer:
wariber [46]2 years ago
7 0

Answer:

The reaction is endothermic

Explanation:

we know that the reactants had to get energy from its surroundings which means that the reaction is endothermic

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The weak interactions between atoms that keep atoms near each other but don't tightly bind them together are called
makkiz [27]

Answer:

Cohesive and adhesive forces.

further, we also have vander waal's forces of attraction

7 0
3 years ago
An atom that contains 22 protons,
Westkost [7]

Answer: 45

Explanation:

Recall that mass number = number of protons + number of neutrons. Hence, the mass number of the atom

= 22 + 23

= 45

Furthermore, the atomic number is equal to the number of protons. Hence, since the number of protons is 22. the atom has an atomic number of 22

Thus, An atom that contains 22 protons,

23 neutrons, and 22 electrons would have a mass of approximately 45

6 0
3 years ago
Read 2 more answers
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
2 years ago
If the half-life of Carbon-14 is 5700 years, how many years would it take a sample to decay from 1 gram to 31.3 mg
andrew-mc [135]

Answer:

28500 years

Explanation:

Applying,

A = A'(2^{x/y})............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313(2^{x/5700})

2^{x/5700} = 1/0.0313

2^{x/5700}  = 31.95

2^{x/5700} ≈ 32

2^{x/5700} ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

3 0
3 years ago
An example of a substance that can be decomposed by a chemical change is:
Savatey [412]

The answer is iron..

7 0
3 years ago
Read 2 more answers
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