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sergiy2304 [10]
3 years ago
10

Evaluate the expression, if possible

Mathematics
2 answers:
barxatty [35]3 years ago
6 0

√(49/25)

= √49 / √25

= 7/5

= 1.4

Answer:

1.4

Bond [772]3 years ago
3 0

Hello,

\sqrt{\dfrac{49}{25}} = \dfrac{7}{5}

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Please explain this problem!!!​
9966 [12]

tis a little of plain differentiation.

we know the radius of the cone is decreasing at 10 mtr/mins, or namely dr/dt = -10, decreasing, meaning is negative.

we know the volume is decreasing at a rate of 1346 mtr/mins or namely dV/dt = -1346, also negative.

so, when h = 9 and V = 307, what is dh/dt in essence.

we'll be needing the "r" value at that instant, so let's get it

V=\cfrac{1}{3}\pi r^2 h\implies 307=\cfrac{\pi }{3}r^2(9)\implies \sqrt{\cfrac{307}{3\pi }}=r

now let's get the derivative of the volume of the cone

V=\cfrac{1}{3}\pi r^2 h\implies \cfrac{dV}{dt}=\cfrac{\pi }{3}\stackrel{product~rule}{ \left[ \underset{chain~rule}{2r\cdot \cfrac{dr}{dt}}\cdot h+r^2\cdot \cfrac{dh}{dt} \right]} \\\\\\ -1346=\cfrac{\pi }{3}\left[2\sqrt{\cfrac{307}{3\pi }}(-10)(9)~~+ ~~ \cfrac{307}{3\pi } \cdot \cfrac{dh}{dt}\right]

-\cfrac{4038}{\pi }=-\cfrac{180\sqrt{307}}{\sqrt{3\pi }}+\cfrac{307}{3\pi } \cdot \cfrac{dh}{dt}\implies \left[ -\cfrac{4038}{\pi }+\cfrac{180\sqrt{307}}{\sqrt{3\pi }} \right]\cfrac{3\pi }{307}=\cfrac{dh}{dt} \\\\\\ -\cfrac{12114}{307}+\cfrac{180\sqrt{3\pi }}{\sqrt{307}}=\cfrac{dh}{dt}\implies -7.920939735970634 \approx \cfrac{dh}{dt}

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2 years ago
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hodyreva [135]

Answer:

The correct answer is third option

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From the figure we can see a right angled triangle ABC.

Right angled at C.

AB = 10

AC = 5

BC = 5√3

<u>Points to remember</u>

Tan θ = Opposite side/Adjacent side

<u>To find the value of tan(B)</u>

Tan B =  Opposite side/Adjacent side

 = AC/BC

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Therefore the value of tan(B) =  1/√3

7 0
4 years ago
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inna [77]

Answer:

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