1. (x^2+1)*(x^3+2*x)*(x^2-64)
=(x^2+1)*x*(x^2+2)*(x+8)(x-8)
Solving for each factor in turn, for example,
x^2+1=0 => x^2=-1 => x=+i, x=-i
x=0 => x=0
x^2+2=0 => x^2=2 => x=+sqrt(2)i, -sqrt(2)i
x+8=0 => x=-8
x-8=0 => x=+8
we have solution set
S, whereS={+i, -i, 0, +sqrt(2)i, -sqrt(2)i, -8, +8)
2. A.
x^4-81=0 => x^4=81 => x^2=+9 or x^2=-9
x^2=+9 => x=+3, -3
x^2=-9 => x=+3i, -3i
S={+3i, -3i, +3, -3}
B.
x^4+10x^2+25=0 => (x^2+5)^2=0 => ± (x^2+5)=0 => x^2=-5
=> x=+sqrt(5)i (multiplicity 2 and x=-sqrt(5)i (multiplicity 2)
S={+sqrt(5)i (multiplicity 2) -sqrt(5)i (multiplicity 2)}
C.
x^4-x^2-6=0 => (x^2-3)(x^2+2)=0 => x^2=3 or x^2=-2
S={+sqrt(2)i,-sqrt(2)i, +sqrt(3), -sqrt(3) }
3.
x^4+3x^2-4=0 = (x^2-1)(x^2+4) => x^2=1 or x^2=-4
S={+2i, -2i, +1, -1}
Answer:
7/66
Step-by-step explanation:
The probability of picking one girl would be 5/12 That is because there are 5 girls out of the 12 students, and the probability of an event occuring is:
of things you want/of things are possible
Using that same logic, the next student should be easier. We reduced the student population by 1, so we have 11 possible ways it can happen now instead of 12, so that gives us 7/11 for the probability of picking a boy as the second pick.
And lastly, using the same logic shown above, the probability of picking a girl on the third pick would be: 4/10
We are not done, though. We have the separate probabilities, but now we have to multiply then together to figure out the probability of this exact event happening:
5/12 * 7/11 * 4/10 = 140/1320
Which when reduced is: 7/66
Step-by-step explanation:
please mark me as brainlest
Answer: 15,000
Step-by-step explanation:
When you subtract 75,000-60,000, you will get 15,000 and 15,000 is the Variance.
Hope this helps! Thanks for asking.
Answer:
C
Step-by-step explanation:
10/4=2.5
2.5x38=95
95 minutes= 1 hour 35 minutes
