Answer:
True! First step is to make objective observations.
Answer:
C) 50 m/s
Explanation:
With the given information we can calculate the acceleration using the force and mass of the box.
Newton's 2nd Law: F = ma
- 5 N = 1 kg * a
- a = 5 m/s²
List out known variables:
- v₀ = 0 m/s
- a = 5 m/s²
- v = ?
- Δx = 250 m
Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:
Substitute known values into the equation and solve for v.
- v² = (0)² + 2(5)(250)
- v² = 2500
- v = 50 m/s
The final velocity of the box is C) 50 m/s.
Answer:
how fast it is moving in m/s? 0.65 m/s.
Explanation:
given information:
the length of the arm, L - 0.9 m
angle, θ = 20°
First we calculate the distance in horizontal motion
s = 2 L sin θ
= 2 (0.9) sin 20°
= 0.62 m
now calculate the time
t/2 = 2π√(L/g)
t = π√(0.9/9.8)
= 0.95 s
the speed is
v = s/t
= 0.62/0.95
= 0.65 m/s
C.
Newton’s Second Law is F=ma (force is equal to the mass multiplied by acceleration), however, the equation can be rearranged to isolate and calculate mass from force over acceleration. Therefore, m=F/a
Answer:
kinetic energy as it involves dispersal of energy