Answer:
2872.8 N
Explanation:
We have the following information
m =n72kg
Δy = 18m
t = 0.95s.
From here we use the equation
Δy=1/2at2 in order to solve for the acceleration.
So a
=( 2x 18m)/(0.95s²)
= 36/0.9025
= 39.9m/s2.
From there we use the equation
F = ma
F=(72kg) x (39.9)
= 2872.8N.
2872.8N is the average net force exerted on him in the barrel of the cannon.
Thank you!
Answer:
Name: Zinc
Symbol: Zn
Atomic Number: 30
Atomic Mass: 65.39 amu
Melting Point: 419.58 °C (692.73 K, 787.24396 °F)
Boiling Point: 907.0 °C (1180.15 K, 1664.6 °F)
Number of Protons/Electrons: 30
Number of Neutrons: 35
Classification: Transition metal
Crystal Structure: Hexagonal
Density at 293 K: 7.133 g/cm3
Color: bluish
('lil long, sorry)
Answer:
From what I see, it's saying that every minute, the ant can move 30 meters. So how many meter would it move in 45 minutes?
30 meters = 1 min
x meters = 45 min
1 min x 45 = 45 min
30 meters x 45 = 1,350 meters
So, I believe the answer would be 1,350 meters.
hope this helps. :>
2.71 m/s fast Hans is moving after the collision.
<u>Explanation</u>:
Given that,
Mass of Jeremy is 120 kg (
)
Speed of Jeremy is 3 m/s (
)
Speed of Jeremy after collision is (
) -2.5 m/s
Mass of Hans is 140 kg (
)
Speed of Hans is -2 m/s (
)
Speed of Hans after collision is (
)
Linear momentum is defined as “mass time’s speed of the vehicle”. Linear momentum before the collision of Jeremy and Hans is
= ![=\mathrm{M}_{1} \times \mathrm{V}_{\mathrm{J}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{H}}](https://tex.z-dn.net/?f=%3D%5Cmathrm%7BM%7D_%7B1%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BJ%7D%7D%2B%5Cmathrm%7BM%7D_%7B%5Cmathrm%7BH%7D%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BH%7D%7D)
Substitute the given values,
= 120 × 3 + 140 × (-2)
= 360 + (-280)
= 80 kg m/s
Linear momentum after the collision of Jeremy and Hans is
= ![=\mathrm{M}_{\mathrm{J}} \times \mathrm{V}_{\mathrm{JA}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{HA}}](https://tex.z-dn.net/?f=%3D%5Cmathrm%7BM%7D_%7B%5Cmathrm%7BJ%7D%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BJA%7D%7D%2B%5Cmathrm%7BM%7D_%7B%5Cmathrm%7BH%7D%7D%20%5Ctimes%20%5Cmathrm%7BV%7D_%7B%5Cmathrm%7BHA%7D%7D)
= 120 × (-2.5) + 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
= -300 + 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
We know that conservation of liner momentum,
Linear momentum before the collision = Linear momentum after the collision
80 = -300 + 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
80 + 300 = 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
380 = 140 × ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
380/140= ![V_{HA}](https://tex.z-dn.net/?f=V_%7BHA%7D)
= 2.71 m/s
2.71 m/s fast Hans is moving after the collision.
Answer:
Ans= 9
See attached picture for clearer solution.
Explanation:
The net electrostatic force acting on charge A = 2/ 2 + 2 /(2) 2 − 2 /(3) 2 = 2 / 2 (1 + 1/4 – 1/9 ) = 41/36 2/2 .
The net electrostatic force acting on charge B = 2/2 + 2/(2)2 − 2/2 = 1/4 2/d2 .
The net electrostatic force acting on charge C = 2/2 + 2/(2)2 + 2/2 = 2/2 (1 + 1 4 + 1) = 9/4 2/2 .
The net electrostatic force acting on charge D = 2/2+ 2 /(2)2 + 2/(3)2 = 2 /2 (1 + 1/4 + 1/9 ) = 49/36 2/ 2 .
The ratio of the largest to the smallest net force = 9/4*2/2 / 1/4 2/2 . = 9