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FinnZ [79.3K]
3 years ago
8

Which event would be impossible to explain by using John Dalton's model of the atom

Chemistry
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

idk

Explanation:

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C-12 has 6 protons.<br> How many neutrons does C-13 have?<br> A. 6<br> B. 7<br> C. 13<br> D. 19
atroni [7]

Answer:

B-7

Explanation:

13-6=7

8 0
3 years ago
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You mix two clear liquids and a colored solid forms at the bottom of the beaker. Do you think this is a chemical change? How can
UkoKoshka [18]
The answer is yes. A chemical change occurred.
Chemical change is defined as the rearrangement or alteration in the of atoms in one or more substance which result in the formation of a new substance.

In the above, you mixed two clear liquids and the result was a new substance which is a colored solid precipitate at the bottom of the beaker.
This means that changes in the atoms of the two clear liquids occurred leading to the formation of this new solid substance.

This means that chemical change has occurred.

Hope this helps :)
7 0
3 years ago
Which of the following ions would represent the ion of an element from Group 2 on the Periodic Table? A2+ Y3+ X2- Z+
Luba_88 [7]
A2+. Group 2 elements form cations with 2+ charge.
7 0
3 years ago
What gas is necessary for combustion to take place
madreJ [45]
Oxygen for complete combustion
6 0
3 years ago
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Suppose that 0.410 mol of methane, CH4(g), is reacted with 0.560 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc
Ber [7]

Answer:

The balanced equation for this reaction will be

                            CH4 + 4F2    →  CF4 + 4HF

We can see that 1 mole of methane requires 4 moles of fluorine but we have 0.41 moles of CH4 and 0.56mole of F2

So using the unitary method we will get that

  • 1 mole of CH4 → 4 mole of 4 mole of fluorine
  • 0.41 mole of methane  →  4*0.41 = 1.64 mole of fluorine for complete reaction

but we have only 0.56 mole of fluorine that means fluorine is the limiting reagent and the product will only be formed by only this amount of fluorine.

  • 4 moles of  fluorine →  1 mole of CF4
  • 0.56 mole →  \frac{1}{4} * 0.56 = 0.14mole of CF4
  • 4 moles of fluorine →  4 moles of HF
  • 0.56 mole of fluorine →  0.56 mole of HF

now to find the heat released we have the formula as

DELTA H = n * Delta H of product - n *delta H of reactant

where n is the moles of the reactant and product.

note: since no information is given about the enthalpies of the species we leave it on general equation also you need to add the product side enthalpy of the species present and similarly on the product side.

8 0
3 years ago
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