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3 years ago

The Periodic Table List 3 elements that belong to the same Group/Family.

Chemistry

2 answers:

gizmo_the_mogwai [7]3 years ago

4 0

Answer:lithium(LI),sodium(NA) and rubidium(RB)

Explanation:

these 3 elements are part of the same family(alkali metals) and group(1)

hichkok12 [17]3 years ago

3 0

Answer:

Lithium,Sodium,Potassium all belong to transition metals

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OLEGan [10]

The answer would be True

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3 years ago

When an atom gains or loses electrons and has and does not have an equal number of

aksik [14]

Answer:

it is called an ion

Explanation:

if it gains electrons then it is an anion

if it gains protons it is a cation

typically non metals are anions and metals are cations

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2 years ago

Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

Nata [24]

<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

8 0

3 years ago

Approximately how many elements are there that combine chemically in a great number of ways to produce compounds? A. 25 B. 50 C

Arturiano [62]

100 as there’s approximately 100 discovered elements

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3 years ago

Read 2 more answers

In the molecule ClF3, chlorine makes three covalent bonds. Therefore, three of its seven valence electrons need to be unpaired.

Kisachek [45]

Answer:

Explanation:

Chlorine has electronic configuration of 2 , 8 , 7

In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration becomes as follows

$3s^23p_x^23p_y^23p_z^1$ = 7

$3s^23p_x^23p_y^13p_z^13d_{xy}^1$

These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )

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3 years ago