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sergij07 [2.7K]
3 years ago
9

Please help I don’t know the answer

Chemistry
1 answer:
trapecia [35]3 years ago
4 0

Answer:

the answer is B, "summer, winter"

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How many grams of hydrogen are contained in 2.00 mol of C6H7N
Setler [38]

Answer:- 14.0 moles of hydrogen present in 2.00 moles of [tex]C_6H_7N .

Solution:- We have been given with 2.00 moles of C_6H_7N and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:

2.00molC_6H_7N(\frac{7molH}{1molC_6H_7N})(\frac{1.0gH}{1molH})

= 14.0 g H

So, there are 14.0 g of hydrogen in 2.00 moles of  C_6H_7N .

3 0
3 years ago
A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t
FrozenT [24]

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

4 0
3 years ago
Where do food molecules for cecropia trees come from?
Oliga [24]

Answer:

Central and South American forests.

Explanation: https://brainly.in/question/7540305

8 0
3 years ago
3690 J of heat are added to a 21.5 g sample
Fiesta28 [93]

Answer:

693K

Explanation:

The enthalpy change in the iron is 3690J

We now apply the formula for enthalpy change which is ΔH=mC∅ where ∅ is the temperature change, m the mass of the substance, and C the specific heat capacity for the substance.

ΔH in this case is 3690J.

Therefore 3690J=21.5g×0.449J/g.K×∅

as we are looking for ∅, we make it the subject of the formula.

∅=3690J/(21.5g×0.44J/g)

∅=390

Temperature=30°C +390

=420°+273

=693K

6 0
3 years ago
Any DBZ fans??????????????????????//<br><br> ??????????????
Mnenie [13.5K]

Answer:

ummmmmmmmmm what's that???

8 0
3 years ago
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