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2 years ago

6

The original amount of radioactive substance is 10 grams. After several years, 2.5 gtams of the substance is remaining. How many

half-lives havr passed since the mass of the subtance was 10 grams?

1 answer:

nirvana33 [79]2 years ago

8 0

10/2=5 (one half life)
5/2=2.5(two half lives)

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kumpel [21]

Answer:

0.17325 moles per liter per second

Explanation:

For a first order reaction;

in[A] = in[A]o - kt

Where;

[A]= concentration at time t

[A]o = initial concentration

k= rate constant

t= time taken

ln0.5 =ln1 - 2k

2k = ln1 - ln0.5

k= ln1 - ln0.5/2

k= 0 -(0.693)/2

k= 0.693/2

k= 0.3465 s-1

Rate of reaction = k[A]

Rate = 0.3465 s-1 × 0.50 mol/L

Rate = 0.17325 moles per liter per second

5 0

2 years ago

1.Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCl) solution (i.e. in a 100 ml of solution there is 6.15 gram

shtirl [24]

Answer:

C U M

Explanation:

3 0

2 years ago

Which substance is a pure substance? <br> Cereal <br> Silver <br> Jelly bean <br> Shampoo

Tju [1.3M]

Silver?

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6 0

3 years ago

Read 2 more answers

Which will have a greater volume: 10 grams of liquid water or 10 grams of solid water?

san4es73 [151]

The volume of 10 grams of frozen water is more than the volume of 10 grams of liquid water

5 0

2 years ago

A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,

lara31 [8.8K]

Answer:

The answer to your question is: T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L V2 = 2.78 L

P1 = 2.40 atm P2 = 1.97 atm

T1 = 325°K T2 = ?

Formula

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Process

T2 = (P2V2T1) / (P1V1)

T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

T2 = 1779.895 / 7.56

T2 = 235.44 °K

4 0

2 years ago