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natima [27]
3 years ago
11

How are nitrogen-14 and nitrogen-15 same and different?

Chemistry
1 answer:
Likurg_2 [28]3 years ago
7 0

Answer:

Since different isotopes of an element have different numbers of neutrons (but always the same number of protons) they have different mass numbers. Nitrogen-14 and nitrogen-15 are both stable isotopes of nitrogen. However, the other 5 isotopes are all unstable.

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A 4.27 g sample of a lab solution contains 1.81g of acid. What is the concentration of the solution as a mass percentage?
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Answer:

42.38875878%

Explanation:

i divided 4.27 g from 1.81g using a percentage calculator but im not sure if its correct

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2 years ago
Which best describes a compound such as magnesium oxide
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A pure substance made up of different elements

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You are comparing a reaction that produces a chemical
MaRussiya [10]

If the reaction is a chemical change, new substances with different properties and identities are formed. This may be indicated by the production of an odor, a change in color or energy, or the formation of a solid.

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¿The presence of which atmospheric condition will most likely result in clear skies in Binghamton, New York?
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Most Likely A High Pressure Center

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3 years ago
300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You
Bas_tet [7]

Explanation:

It is given that volume of Pb(NO_{3})_{2} is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

            PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)

K_{sp} for PbCl_{2} is given as 1.7 \times 10^{-5}.

As, molarity is number of moles present in liter of solution.

Hence, moles of Pb^{2+}(aq) will be calculated as follows.

         moles of Pb^{2+}(aq) = 0.300 L \times 0.200 M

                                                = 0.06 mol

                      [Pb^{2+}] = \frac{0.06 mol}{0.5 L}

                                            = 0.120 M

Mole of Cl^{-}(aq) = 0.2 L \times 0.05 M  

                                  = 0.010 M

Now,   Q = [Pb^{2+}][Cl^{-}]^{2}

                  = 0.120 \times (0.010)^{2}

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As, Q < K_{sp} hence, there will be no formation of PbCl_{2} precipitate.

3 0
3 years ago
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