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Ganezh [65]
3 years ago
5

Three expresions for 20% of48

Mathematics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

9.6

Step-by-step explanation:

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Find the absolute value of 4k-4.
lukranit [14]
It might be k, since 4-4 is 0 and 0 has no absolute value.
4 0
3 years ago
Albert jumped 100 times in 97.5 seconds. Round off the time taken to the nearest second.​
KonstantinChe [14]
Answer
98 seconds
Step by step explanation
The reason being is that .5 would be millisecond and 5 will round up making the answer be 98 seconds
5 0
3 years ago
What is the vertex of g(x) = -3x2 + 18x + 2?<br> (3, -25)<br> (-3, -25)<br> O (3, 29)<br> (-3, 29)
Amanda [17]

Answer:

(3,29)

Step-by-step explanation:

=-3(x2-6x)+2

=-3(x2-6x+9)+2+27

=-3(x-3)2+29,so the vertex will be (3,29)

4 0
3 years ago
Read 2 more answers
How to calulate how high a tree that is 5m high and shadow is 4m?
Deffense [45]
If you are trying to figure out the distance between the top of the tree and the end of the shadow, use a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the legs of the right triangle.
5^2 + 4^2 = c^2
25 + 16 = c^2
41 = c^2
c = √41 = 6.4 meters
3 0
3 years ago
6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
riadik2000 [5.3K]

Answer:

404 cm³ Anyway... Look down here for my explanation.

Step-by-step explanation:

Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.

We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)

44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°

The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.

Shaded area 88.8/360*area of circle - ½*7*788.8°

= 88.8/360*π*7² - 24.5*sin 88.8°

13.5 cm²

(using area of ∆ = ½.a.b.sin C for the triangle)

Volume of water = cross-sectional area * length

13.5 * 30 cm³

404 cm³

6 0
2 years ago
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