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kirill115 [55]
4 years ago
11

In these formulas, it is useful to understand which variables are parameters that specify the nature of the wave. The variables

E0 and B0 are the __________ of the electric and magnetic fields.
Physics
1 answer:
saveliy_v [14]4 years ago
4 0

Answer:

In these formulas, it is useful to understand which variables are parameters that specify the nature of the wave. The variables E₀ and B₀ are the amplitudes of the electric and magnetic fields.

Explanation:

Generally, the variables that specify the nature of the wave are:

(1) The amplitude of the electric field, designated as E₀, and

(2) The amplitude of the electric field, designated as B₀.

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What causes light to bend when it moves from one transport medium to another
faltersainse [42]

Answer:

The bending of light as it passes from one medium to another is called refraction. The angle and wavelength at which the light enters a substance and the density of that substance determine how much the light is refracted. The bending occurs because light travels more slowly in a denser medium.

hope this helped :))

5 0
3 years ago
a car collides with a wall. compare the forces exerted by the car on the wall and the wall on the car​
NeTakaya

Mass multiplied by acceleration produces force.

The acceleration is (v - 0)/t in this situation, where t seems to be the time it takes automobile A to come to a stop. According to Newton's third law of motion, the automobile produces this turning force of the wall, however the wall, which really is static and indestructible, forces an equal force back on the car.

According to Newton's third law, each action has an equal and opposite response. On this basis, you may deduce that a car driving into a wall would exert force on the wall. However, since the wall did not move, the automobile receives an equivalent force, causing it to collapse.

<h3>Learn more:</h3>

brainly.com/question/13952508?referrer=searchResults

5 0
2 years ago
Read 2 more answers
A light wave traveling through medium 1 strikes a boundary with medium 2 at at a 45 degree angle. the light then enters the seco
Alona [7]

Here light ray strikes to interface at an angle of 45 degree and then refracts into other medium such that it will bend towards boundary.

So here the angle of incidence will be less than the angle of refraction as light moves towards the boundary after refraction which mean it will bend away from the normal

here it can be said that medium 2 will be rarer then medium 1

So here the possible options are

1. Water  

Air

2. Diamond  

Air

So in above two options medium 1 is denser and medium 2 is rarer

8 0
3 years ago
A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

mass of m_2=0.8 kg dropped at r=0.3 m from center

let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

L_1=L_2

\left ( \frac{m_1R^2}{2}\right )\omega =\left ( \frac{m_1R^2}{2}+m_2r^2\right )\omega _2

\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

26.01\times 40=26.082\times \omega _2

\omega _2=39.88 rad/s

3 0
4 years ago
The volume of an ideal gas is adiabatically reduced from 151 L to 80.6 L. The initial pressure and temperature are 1.50 atm and
Zolol [24]

Answer:

gas is dioatomic

T_f = 330.0 K

\eta = 7.07 mole

Explanation:

Part 1

below equation is used to determine the type Gas by determining \gamma value

\frac{V_{1}}{V_{F}}\gamma=\frac{P_{i}}{P_{f}}

where V_i and V_f is initial and final volume respectively

and P_i and P_f are initial and final pressure

\gamma = \frac{ln(P_f/P_i)}{ln(V_i/V_f)}

\gamma = \frac{ln(3.61/1.50)}{ln(151/80.6}

\gamma = 1.38

therefore gas is dioatomic

Part 2

final temperature in adiabatic process is given as

T_f = T_i*[\frac{v_i}{V_f}](^\gamma-1)

substituing value to get final temperature

T_f = 260*[\frac{151}{80.6}]^ {(1.38-1)}

T_f = 330.0 K

Part 3

determine number of moles by using following formula

\eta =\frac{PV}{RT}

\eta =\frac{1.013*10^{5}*0.151}{8.314*260}

\eta = 7.07 mole

4 0
3 years ago
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