Question

How many kilojoules of heat are required to heat 1.37kg of water from 21.3 to 89.5

Answer 1

Q= ? kJ                  
m= 1.37 kg × $\frac{1000 g}{1kg}$ =1370 g
                      
c=4.18 J/g° C
ΔΤ= 89.5-21.3= 68.2˚C
? J = (1370 g) (4.18 J/g˚C) (68.2˚C)
q = 390,554 J× $\frac{1kJ}{1000J}$
                 
                    q = 391 kJ