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yanalaym [24]
3 years ago
5

What is the numerical solution of sec^2(-pi/4)?

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0
Sec²(-π/4)

sec x= 1/ cos x
cos(-π/4)=cos(π/4)  as even function
cos(π/4) = (√2)/2
sec(-π/4) =1/(cos(-π/4))=1/cos(π/4)= 2/(√2)

sec²(-π/4)=( 2/(√2))²= 4/2=2

sec²(-π/4) = 2

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Hitman42 [59]
It is b. 82! because it keeps going up by 2’s so 26+11 is 37. 37 +13 is 50. 50+ 15 is 82. please tell me if i’m correct
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Justina spent $2.50 on a keychain. This amount was of the total amount of money she 8 1had. How much money did Justina have?
mafiozo [28]

Answer:

Amount she has now = $5.5

Step-by-step explanation:

Given:

Amount of Money had = $8

Money spent = $2.50

Find:

Amount she has now

Computation:

Amount she has now = Amount of Money had - Money spent

Amount she has now = $8 - $2.50

Amount she has now = $5.5

5 0
3 years ago
How to solve 2x+3=9x-11
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2x+3=9x-11 \ \ |\ subtract\ 9x \ and \ 3\ to\ both\ sides\\\\2x+3 -9x -3=9x-11-9x-3\\\\-7x =-14    \ \ | \ divide \ both \ sides\  by\   (-7)\\\\x=2
8 0
3 years ago
Read 2 more answers
Help me!!!
nadya68 [22]

Step-by-step explanation:

You would start by using one of the equations to find y with x in the equation. You want to pick the easier one. I picked this one because it was evenly divisible.

5x+5y=50

5x=-5y+50

x=-y+10

Then you what to plug that in to the second equation and solve for y.

3(-y+10)+4y=32

-3y+30+4y=32

-3y+4y=2

y=2 (because you combined like terms)

Then you would plug back into the first equation and solve for x.

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8 0
4 years ago
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ryzh [129]

Answer:

(1 ) Inner curved surface area of the well is  109.9 sq. meters.

(2) The cost of plastering the total curved surface area is  4396.

Step-by-step explanation:

The inner diameter = 3.5 m

Depth of the well =  10 m

Now, Diameter = 2 x Radius

⇒R = D/ 2  = 3.5/2 = 1.75

or, the inner radius of the well = 1.75 m

CURVED SURFACE AREA of cylinder = 2πr h

⇒The inner curved surface area =  2πr h  = 2 ( 3.14) (1.75)(10)

                                                                      = 109 sq. meters

Hence, the inner curved surface area of the well is  109.9 sq. meters.

Now, the cost of plastering the curved area is 40 per sq meters

So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)

                                                                    =  109.9 x (40)

                                                                   =   4396

Hence, the cost of plastering the total curved surface area is  4396.

8 0
4 years ago
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