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yanalaym [24]
3 years ago
5

What is the numerical solution of sec^2(-pi/4)?

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0
Sec²(-π/4)

sec x= 1/ cos x
cos(-π/4)=cos(π/4)  as even function
cos(π/4) = (√2)/2
sec(-π/4) =1/(cos(-π/4))=1/cos(π/4)= 2/(√2)

sec²(-π/4)=( 2/(√2))²= 4/2=2

sec²(-π/4) = 2

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3 years ago
In a lottery game, a single ball is drawn at random from a container that contains 25 identical balls numbered from 1 through 25
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Answer:

17/25

Step-by-step explanation:

The equation for the probability of two events that are not mutually exclusive is:

p(A ∨ B) = p(A) + p(B) - p(A ∧ B)

A = the number is prime

B = the number is prime

The numbers are:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

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p(A) = 8/25

Here are the 13 numbers that are greater than 12 that satisfy event B:

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p(B) = 13/25

Here are the 4 numbers that satisfy both event A and event B:

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7 0
2 years ago
In general, the point
Zanzabum

Answer:

we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.

Therefore, the point (0, a) is on the graph of the function f(x) = abˣ

Hence, option (D) is correct.

Step-by-step explanation:

Given the function

f(x) = abˣ

Let us substitute all the points one by one

FOR (b, 0)

y = abˣ

putting x = b, y = 0

0 = abᵇ

FOR (a, b)

y = abˣ

putting x = a, y = b

b = abᵃ

FOR (0, 0)

y = abˣ

putting x = 0, y = 0

0 = ab⁰

0 = a         ∵b⁰ = 1

FOR (0, a)

y = abˣ

putting x = 0, y = a

a = ab⁰

a = a         ∵b⁰ = 1

TRUE

Thus, we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.

Therefore, the point (0, a) is on the graph of the function f(x) = abˣ

Hence, option (D) is correct.

8 0
3 years ago
A local little league has a total of 75 ​players, of whom 20​% are right​-handed. How many
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Answer:

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Step-by-step explanation:

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