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just olya [345]
3 years ago
14

The molar mass of glucose is 180 grams per mole (g/mol). Which of the following procedures should you carry out to make a 1 M so

lution of glucose? In 0.8 liter (L) of water, dissolve ________.
Chemistry
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

You need to dissolve 144 gr of glucose in 0.8 liters of water to have a 1 M solution.

Explanation:

Molarity is the amount of moles per liter of solution --> moles/liters. We are trying to get a 1 molar solution and we also know the liters (0,8L) so

1\frac {moles-of-glucose}{liters-of-water} =\frac{X moles-of-glucose}{0.8 liters-of-water} \\

1\frac{Moles-of-glucose}{liters-of-water } * 0.8 liters of water

after canceling liters of water you get 0,8 moles of glucose.

180 \frac{grams-of-glucose}{mol-of-glucose}*0.8 mol- of- glucose=144 grams-of-glucose

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A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

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Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

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use:

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= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0
3 years ago
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