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just olya [345]
3 years ago
14

The molar mass of glucose is 180 grams per mole (g/mol). Which of the following procedures should you carry out to make a 1 M so

lution of glucose? In 0.8 liter (L) of water, dissolve ________.
Chemistry
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

You need to dissolve 144 gr of glucose in 0.8 liters of water to have a 1 M solution.

Explanation:

Molarity is the amount of moles per liter of solution --> moles/liters. We are trying to get a 1 molar solution and we also know the liters (0,8L) so

1\frac {moles-of-glucose}{liters-of-water} =\frac{X moles-of-glucose}{0.8 liters-of-water} \\

1\frac{Moles-of-glucose}{liters-of-water } * 0.8 liters of water

after canceling liters of water you get 0,8 moles of glucose.

180 \frac{grams-of-glucose}{mol-of-glucose}*0.8 mol- of- glucose=144 grams-of-glucose

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The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

2. H_{2}CO_{3}

Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
Chemistry help please! I just need to make sure the answers correct.... Thank you!
Veronika [31]
1. At constant tempaerature and pressure, 3 tablets produce 600cm^3 of gas
Thus calculating for 1 tablet that produces 600 / 3 = 200 cm^3
So now two tablets produce 200 x 2 = 400 cm^3
2. We have the equation PV = nRT, n being the number of moles
Pressure P = 1,000 kPa
Volume V = 3 L
R = 8.31 L kPa/mol-K
Temperature T = 298 K
n = PV / RT = (1000 x 3) / (8.31 x 298) = 3000 / 2476.38 = 1.21 moles
Number of moles = 1.21 moles.
8 0
3 years ago
Which of the following are good conductors
dimulka [17.4K]

Answer:

iron, graphite,NaCl solution etc are some examples of good conductor of electricity

5 0
3 years ago
Read 2 more answers
What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?
zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

3 0
3 years ago
What increases acidity more, nitrile group or chloride group?
lozanna [386]

Answer:

The nitrile group

Explanation:

The nitrile group contains the C≡N bond. It should be recalled that triple bond is highly electronegative and withdraws electrons from the C-H bond more effectively than the halogen atom.

The higher effectiveness of the C≡N bond at electron withdrawal greatly reduces the electron density of the C-H bond thereby making the hydrogen atom of the bond highly labile

8 0
3 years ago
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