Answer:
The image height is 3.0 cm
Explanation:
Given;
object distance, = 15.0 cm
image distance, = 5.0 cm
height of the object, = 9.0 cm
height of the image, = ?
Apply lens equation;
Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.
Answer:
a. the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon
Explanation:
F= ma
v²=u² -2aS
(1.56 ✕ 10⁶)²=(2.40 ✕ 10⁶)²-2a(1220)
a=1.36×10⁹m/s²
recall
F=ma
F = 1.88 ✕ 10⁻²⁸ kg × 1.36×10⁹m/s²
F= 2.55 × 10⁻¹⁹N
the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon
F/mg= 2.55 × 10⁻¹⁹/ (1.88 ✕ 10⁻²⁸ × 9.8)
= 1.38 × 10⁸
Answer: 4.03 m/s
Explanation: Kinetic energy is
KE = 1/2 m v²
So we derive the equation to have v.
v = √ 2KE / m
= 2 x 568 J / 70 kg
= 16.23
= √ 16.23
= 4.03 m/s
Given that,
Horizontal force, F = 600 N
A mover pushes a dresser 9 meters across a bedroom.
To find,
The work done by the mover.
Solution,
The work done by an object is given by :
W = Fd
Where d is distance
W = 600 N × 9 m
= 5400 J
So, the work done by the mover is 5400 J.