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laiz [17]
2 years ago
15

Derive the value of electric field due to a uniform sphere of charge.

Physics
1 answer:
Deffense [45]2 years ago
4 0
<h2>Hey there!</h2>

The Force "F" applied on the unit electric charge "q" at a point describes the electric field.

<h3>☆ Formula to find electric charge:</h3>

  • E = F/q

<h2>Hope it helps </h2>
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____________ interference occurs when two waves are out of phase
EleoNora [17]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Wave Optics.

Whenever the waves are out of phase they form a DESTRUCTIVE interference.

thus,

Destructive Interference occurs when two waves are out of phase.

5 0
3 years ago
A substance with a pH of 9 has
Lady bird [3.3K]

A) no H30+ ions or OH- ions.
3 0
3 years ago
Lifting a box off the floor is an example of what type of force?
s2008m [1.1K]
Gravitational I think would be the answer, Hope this helps!
8 0
3 years ago
Read 2 more answers
If the mass of a material is 111 grams and the volume of the material is 23 cm3, what would the density of the material be? g/cm
Butoxors [25]
Density can be kg/m^3 or g/cm3
In g/cm3 density =mass /volume =111g/23cm3
=4.826g/cm3.

In kg/m3,density=mass/volume. converting mass in grams to kg, 1000g=1kg,111g=0.111kg.
cm3 to m3, 1cm3=10^-6m3, 23cm3=0.000023m3
density=0.111kg/0.000023m3 or 2.3*10^-5=4,826.1kg/m3.

the other is a long process.
4 0
3 years ago
When a certain air-filled parallel-plate capacitor is connected across a battery, it acquires a charge of magnitude 172 μC on ea
crimeas [40]

Answer:

k = 2.279

Explanation:

Given:

Magnitude of charge on each plate, Q = 172 μC

Now,

the capacitance, C of a capacitor is given as:

C = Q/V

where,

V is the potential difference

Thus, the capacitance due to the charge of 172 μC will be

C = \frac{(172\ \mu C)}{V}

Now, when the when the additional charge is accumulated

the capacitance (C') will be

C' = \frac{(172+220)\ \mu C)}{V}

or

C' = \frac{(392)\ \mu C)}{V}

now the dielectric constant (k) is given as:

k=\frac{C'}{C}

substituting the values, we get

k=\frac{\frac{(392\ \mu C)}{V}}{\frac{(172)\ \mu C)}{V}}

or

k = 2.279

6 0
4 years ago
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