We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
create a line between (0,0) and (1,3)
the unit rate is 3/2 or 1.5
Step-by-step explanation:
pls mark
Opening the brackets we get = 3xy<span> X </span>4xy<span> + </span>3xy<span> X </span>2<span> - </span>4xy<span> - </span>2<span> = 12x^</span><span>2</span>
Answer:
The 1st one is 540π
The 2nd one is 1696.46
Step-by-step explanation:
To find the volume of a cylinder, you do the following:

Where r represents the radius of the circle and h represents the height. Because it's multiplication, we can change it to:

So since the radius is 6, 6^2 is 36. Then we multiply by 15, to get 540. Then now since we don't need to multiply the pi, you just leave it as 540π.
For the second one, multiply 540 by pi to get the answer, then round it to the nearest hudredth to get 1696.46.