Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck
PWC operators must keep in mind that a jet drive needs moving water through the drive nozzle for maneuverability. In other term, you must have power applied in order to uphold steering control. If the engine shuts off during operation or If you release the throttle to idle, you will lose all steering control. In either situation, the PWC will remain in the direction it was headed before the throttle was released or the engine was shut off. Action of the steering control will have no outcome. If you are approaching a dock, shore, or other vessel at a speed bigger than you can control and you release the throttle to idle or shut off the engine, you won’t have maneuvering capability and the PWC will stay its forward movement.
Answer:Geography, Earth Science, Astronomy
Rotation describes the circular motion of an object around its center.
Explanation:
C. The work done by the 5500.0 N force on the elevator is 275,000 J.
<h3>
Work done by the applied force</h3>
The work done by the 5500.0 N force on the elevator is calculated as follows;
W = Fd
where;
- F is the applied force
- d is the displacement
W = 5500 x 50
W = 275,000 J
Thus, the work done by the 5500.0 N force on the elevator is 275,000 J.
Learn more about work done here: brainly.com/question/8119756
#SPJ1
Answer is: <span>1/4 its old kinetic energy .
</span>V₁ = 10 m/s.
V₂ = 5 m/s.
m₁ = m₂ = m.
E₁ = 1/2 · m₁ · V₁², E₁ = 1/2 · m · (10 m/s)² = 50 · m.
E₂ = 1/2 · m₂ · V₂², E₂ = 1/2 · m · (5 m/s)² = 12,5 · m.
E₂/E₁ = 12,5m / 50m = 0,25.
V - speed of semi-truck.
m - mass of semi-truck.
E - kinetic energy of semi-truck.
