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Oxana [17]
3 years ago
8

ANSWER ASAP

Physics
2 answers:
Temka [501]3 years ago
8 0
5.6 g/ml is the answer
shtirl [24]3 years ago
5 0
5.6 g/ml. That is the density.
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In the average US household, the television is on 6.75 hours/day! How many hours will have passed after 77.7 years (the average
Nady [450]

Answer:

191433.4 hours

Explanation:

We are given that In the average US household, the television is on 6.75 hours/day! How many hours will have passed after 77.7 years (the average lifeexpectancy of an American)?

1 year - 365 days

Given that the television is on 6.75 hours/day.

If 1 year = 365 days

Convert 77.7 years to days by multiplying it by 365

77.7 × 365 = 28360.5 days

So the number of hours will be:

28360.5 × 6.75 = 191433.375 hours

Therefore, 191433.4 hours will pass.

Non of the options is correct.

6 0
3 years ago
PLEASE HELP! Can you do the write about it! Will thank and try to mark brainiest!
goblinko [34]
Move the objects faster to get more friction.
8 0
3 years ago
Read 2 more answers
Answer these two questions please
Grace [21]
1.The answer is True
2.The answer is False
8 0
3 years ago
I need c only please answer it
Elodia [21]
It will be moving at high speeds
5 0
3 years ago
Cierto volumen de gas se encuentra a 60°c de temperatura y 5atm de presión, es calentado hasta 140°c, estado en el cual ocupa un
earnstyle [38]

Answer:

V1 = 2221.33 L

Explanation:

The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

P_1V_1=nRT_1   (1)

And also for the situation in which the variables T, V and P has changed:

P_2V_2=nRT_2   (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}

Next, you equal these equations an solve for T2:

\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}

Finally you replace the values of P2, V2, T1 and T2:

V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L

Hence, the initial volume of the gas is 2221.33 L

5 0
3 years ago
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