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3 years ago

ANSWER ASAP

Physics

2 answers:

Temka [501]3 years ago

8 0

5.6 g/ml is the answer

shtirl [24]3 years ago

5 0

5.6 g/ml. That is the density.

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What do tendons connect skeletal muscles to?

Doss [256]

Answer:

Tendons connect muscle to bone. These tough, yet flexible, bands of fibrous tissue attach the skeletal muscles to the bones they move. Essentially, tendons enable you to move; think of them as intermediaries between muscles and bones.

Hope this helps! (:

6 0

2 years ago

Read 2 more answers

Represent 7468 N with SI units having an appropriate prefix. Express your answer to four significant figures and include the app

Musya8 [376]

Answer:

7.468 kN

Explanation:

Here the force is given in Newton

Some of the prefixes of the SI units are

kilo = 10³

Mega = 10⁶

Giga = 10⁹

Tera = 10¹²

The number is 7468.0

Here, the only solution where the number of significant figures is kilo. If any other prefix is chosen then the significant figures will increase.

1 kilonewton = 1000 Newton

$1\ Newton=\frac{1}{1000}\ kilonewton$

$\\\Rightarrow 7468\ Newton=\frac{7468}{1000}\ kilonewton\\ =7.468\ kilonewton$

So, 7468 N = 7.468 kN

7 0

3 years ago

When objects are forced to vibrate ( like when dropped onto a hard surface), they will do so at their

Marat540 [252]

They'll vibrate at their characteristic resonant frequency. That depends on the material the object is made of and its shape.

3 0

3 years ago

HELP THIS LAST DAY!!!

Alex_Xolod [135]

Answer:

The proton has much greater mass

Explanation:

Protons and electrons are part of an atom
Proton exists inside nucleus whereas electron keep moving around the nucleus
Electrons have negative charge where as protons have positive charge .

8 0

2 years ago

Read 2 more answers

You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In j

Feliz [49]

The potential energy of the spring is 6.75 J

The elastic potential energy stored in the spring is given by the equation:

$E= \frac{1}{2} kx^2$

where;

k is the spring constant

x is the compression/stretching of the string

In this problem, we have the spring as follows:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting in the equation, we get

$E=\frac{1}{2} (150) (0.3)^2$

$E=6.75J$

Therefore. the elastic potential energy stored in the spring is 6.75J .

Learn more about potential energy here:

brainly.com/question/10770261

#SPJ4

6 0

1 year ago