Question

PLEASE ANSWER!!!!

Answer 1

Acceleration of the car is given by

$a = \frac{v_f - v_i}{t}$

$a = \frac{7.5 - 0}{0.30}$

$a = 25 m/s^2$

Mass is given as m = 2580 kg

Now force is given by

$F = ma$

$F = 2580 * 25$

$F = 64500 N$

Now if air bags are open and the time is increased to t = 1 minute.

acceleration is given by

$a = \frac{7.5 - 0}{60}$

$a = 0.125 m/s^2$

Now force is given by

$F = ma$

$F = 2580 * 0.125$

$F = 322.5 N$

So the force is reduced when air bags are opened.