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4 years ago

What do parallel circuits look like

Physics

1 answer:

Scilla [17]4 years ago

3 0

Parallel resistors essentially have the same beginning point and ending point on a circuit. because of this, the voltage across each should be the same and the current across each should equal the total current of the circuit.

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One model for a certain planet has a core of radius R and mass M surrounded by an outer shell of inner radius R, outer radius 2R

Tanzania [10]

(a) $24.6 m/s^2$

At a distance r=R from the centre of the planet, there is no effect due to the outer shell: so, the gravitational field strength at r=R is only determined by the gravity produced by the core of the planet.

So, the strength of the gravitational field is given by

$g= \frac{GM}{R^2}$

where

G is the gravitational constant

M = 6.24 × 10^24 kg is the mass of the core of the planet

R = 4.11 × 10^6 m is the radius of the core

Substituting into the equation, we find

$g= \frac{(6.67\cdot 10^{-11})(6.24\cdot 10^{24} kg)}{(4.11\cdot 10^6 m)^2}=24.6 m/s^2$

(b) $13.7 m/s^2$

at distance r=3R from the centre, the particle feels the effect of gravity due to both the core of the planet and the outer shell between R and 2R.

So, we have to consider the total mass that exerts the gravitational attraction at r=3R, which is the sum of the mass of the core (M) and the mass of the shell (4M):

M' = M + 4M = 5M

Therefore, the gravitational acceleration at r=3R will be

$g'= \frac{G(5M)}{(3R)^2}=\frac{5}{9}\frac{GM}{R^2} = \frac{5}{9}g$

And susbstituting

g = 24.6 m/s^2

found in the previous part, we find

$g' = \frac{5}{9} (24.6 m/s^2)=13.7 m/s^2$

6 0

3 years ago

Which statement is a scientific theory?

Dmitry [639]

Answer:

I think it is D

Explanation:

7 0

3 years ago

Read 2 more answers

∁=f

Sindrei [870]

Answer:

so you have a question

Explanation:

either way have a nice day

5 0

3 years ago

25 POINTS FOR CORRECT ANSWER

castortr0y [4]

No. I do not agree with Stefan. Quite the contrary. I disagree
with his description of "angle of incidence" as the angle between
the surface of the mirror and the incoming ray.

The correct description of "angle of incidence" is the angle between
the NORMAL TO the surface of the mirror and the incoming ray.

Thus, the true angle of incidence is the complement of the angle that
Stefan calculates or measures.

5 0

3 years ago

Read 2 more answers

A pipe open only at one end has a fundamental frequency of 266 Hz. A second pipe, initially identical to the first pipe, is shor

Alika [10]

Answer:

1.16cm were cut off the end of the second pipe

Explanation:

The fundamental frequency in the first pipe is,

Since the speed of sound is not given in the question, we would assume it to be 340m/s

f1 = v/4L, where v is the speed of sound and L is the length of the pipe

266 = 340/4L

L = 0.31954 m = 0.32 m

It is given that the second pipe is identical to the first pipe by cutting off a portion of the open end. So, consider L’ be the length that was cut from the first pipe.

So, the length of the second pipe is L – L’

Then, the fundamental frequency in the second pipe is

f2 = v/4(L - L’)

The beat frequency due to the fundamental frequencies of the first and second pipe is

f2 – f1 = 10hz

[v/4(L - L’)] – 266 = 10

[v/4(L – L’)] = 10 + 266

[v/4(L – L’)] = 276

(L - L’) = v/(4 x 276)

(L – L’) = 340/(4 x 276)

(L – L’) = 0.30797

L’ = 0.31954 – 0.30797

L’ = 0.01157 m = 1.157 cm ≅ 1.16cm

Hence, 1.16 cm were cut from the end of the second pipe

6 0

3 years ago