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olga2289 [7]
3 years ago
12

The temperature of a body of water influences _____

Physics
2 answers:
Dvinal [7]3 years ago
8 0

Answer

The temperature of a body of water influences<u> by surrounding temprature or the temprature of air which blows upon it.</u>

<u>Explanation</u>

If the temperature of air which blow upon the surface of water is high that time there will be transfer of heat from air to surface water due to which temperature of water body will rise. Similarly if the temperature of air which blow upon the surface of water is low that time there will be transfer of heat from  water bodies to surrounding air due to which temperature of water body will fall.

Maslowich3 years ago
5 0
The temperature of the air above it
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A long string is wrapped around a 6.6-cm-diameter cylinder, initially at rest, that is free to rotate on an axle. The string is
lys-0071 [83]

Answer:

\omega_f=571.42\ rpm

Explanation:

It is given that,

Diameter of cylinder, d = 6.6 cm

Radius of cylinder, r = 3.3 cm = 0.033 m

Acceleration of the string, a=1.5\ m/s^2

Displacement, d = 1.3 m

The angular acceleration is given by :

\alpha =\dfrac{a}{r}

\alpha =\dfrac{1.5}{0.033}

\alpha =45.46\ rad/s^2

The angular displacement is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{1.3}{0.033}

\theta=39.39\ rad

Using the third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta

Here, \omega_i=0

\omega_f=\sqrt{2\alpha \theta}

\omega_f=\sqrt{2\times 45.46\times 39.39}

\omega_f=59.84\ rad/s

Since, 1 rad/s = 9.54 rpm

So,

\omega_f=571.42\ rpm

So, the angular speed of the cylinder is 571.42 rpm. Hence, this is the required solution.

5 0
3 years ago
A wagon full of manure accidentally rolls down a driveway for 5.0m while a person pushes against the wagon with a force of 420 N
Cerrena [4.2K]

Answer:

2100 J

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Parameters given:

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Distance moved by object, d = 5m

The change in kinetic energy of an object is equal to the work done by a force acting on the object:

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∆KE = F * d

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∆KE = 2100 J

8 0
3 years ago
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Answer:

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3 years ago
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A weightlifter lifts a set of weights a vertical distance of 2.00m.If a constant net force of 350 N is exerted on the weights,wh
MrMuchimi

Answer:

<em>W=700 Joule</em>

Explanation:

<u>Physics Work </u>

Is the dot product of the force vector by the displacement vector

W=\vec F \cdot \vec r

When both the force and the displacements are pointed in the same direction, the formula reduces to its scalar version

W=F.d

The weightlifter is applying a net force of 350 N to lift the weights a distance of 2 m, thus the net work done is

W=350\ N\ .\ 2\ m=700\ Joule

4 0
4 years ago
PLZ HELP FAST! Which two statements help explain why digital storage of data is so reliable?
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Answer:

C and D

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3 years ago
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