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olga2289 [7]
2 years ago
12

The temperature of a body of water influences _____

Physics
2 answers:
Dvinal [7]2 years ago
8 0

Answer

The temperature of a body of water influences<u> by surrounding temprature or the temprature of air which blows upon it.</u>

<u>Explanation</u>

If the temperature of air which blow upon the surface of water is high that time there will be transfer of heat from air to surface water due to which temperature of water body will rise. Similarly if the temperature of air which blow upon the surface of water is low that time there will be transfer of heat from  water bodies to surrounding air due to which temperature of water body will fall.

Maslowich2 years ago
5 0
The temperature of the air above it
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An electric heating element has a resistance of 16 Ω and is connected to a voltage of 120 V. How much current will flow in this
sergeinik [125]

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All three 'choices' are true.

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The measure of how much salt will dissolve into 100g of water is _______________ .
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A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
ser-zykov [4K]

Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

                       = 8.17 N/m

The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

5 0
2 years ago
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Lubov Fominskaja [6]

Answer:

I think option A is correct

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hope it helps

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